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Scilla [17]
3 years ago
11

Jimmy, Joe and sally are racing their cars. Jimmy and Joe have completed the same number of laps- six fewer laps than Sally. If

the total number of completed laps is 222, ow many laps has each of the three racers completed?
Mathematics
1 answer:
shusha [124]3 years ago
3 0
X = the number of laps Joe has ran.
x + x + x + 6 = 222
3x = 216
x = 72
Jimmy ran 72 laps.
Joe ran 72 laps.
Sally ran 78 laps.
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Peter decided to buy a new car. He made a $2,160 down payment and then took a 48-month loan. The total amount for the car, plus
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Please help. If you answer correctly and give an explanation I'll give you 5 stars, thanks, and brainliest.
timama [110]

The solution of the equation is  x=\frac{11}{7}

Step-by-step explanation:

To simplify an equation of x

  • Simplify each side of the equation
  • Collect x in side and the numerical terms in the other side
  • Find the value of x

∵ The equation is 2x + \frac{1-x}{4}=3

- Multiply all terms of the equation by 4 to cancel the denominator

 of the 2nd term in the left hand side

∵ The equation is 4(2x) +4 (\frac{1-x}{4})=4(3)

∴ 8x + (1 - x) = 12

∴ 8x + 1 - x = 12

- Add like terms

∴ (8x - x) + 1 = 12

∴ 7x + 1 = 12

- Subtract 1 from both sides

∴ 7x = 11

- Divide both sides by 7

∴ x=\frac{11}{7}

The solution of the equation is  x=\frac{11}{7}

Learn more:

You can learn more about the solution of an equation in brainly.com/question/11306893

#LearnwithBrainly

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Anyone knows how to do this ?
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The number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9 is . The probabi
Tems11 [23]

Answer:

1/15

Step-by-step explanation:

When we form such three-digit numbers with distinct digits using the digits  1 , 2 , 3 , 5 , 8  and  9  (in all six digits all different), observe that the order of digits does matter. For example, if we make a number using digits  1 , 2 ,  and  3 , we can have  123 , 132 , 231 , 213 , 312  or  321 .

Hence we have to find number of  3  digit numbers that can be made from these six digits using permutation and answer is ⁶ P ₃ =  6  ×  5  ×  4  =  120 .

.How haw many of them will have first digit as even, we have two choices  2  and  8 . Once we have chosen  2

for hundreds place, we can have only  8  in units place and any one of remaining  4  can be used in tens place. Hence four choices, with  2  in hundreds place and another four choices when we have  8  in hundreds place (and  2  in units place) i.e. total 8  possibilities.

Hence, the probability, that both the first digit and the last digit of the three digit number are even numbers, is  8  /120  =  1 /15

.

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