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Tatiana [17]
2 years ago
6

KDS Company has 3 departments: 1. Dept X 2. Dept Y 3. Dept Z. Design a program that will read as input each department's sales f

or each quarter of the year, and display the result for all divisions.
Computers and Technology
1 answer:
stiv31 [10]2 years ago
6 0

Complete Question:

Design a program that will use a pair of nested loops to read the company's sales amounts. The details are as follows: -

KDS Company has 3 departments: 1. Dept X 2. Dept Y 3. Dept Z. Design a program that will read as input each department's sales for each quarter of the year and display the result for all divisions. Use a two-dimensional array that will have 3 rows and 4 columns

Answer:

In C++:

#include<iostream>  

using namespace std;  

int main() {  

   int depts[3][4];

   char dptcod [3] ={'X','Y','Z'};

   for (int rrw = 0; rrw < 3; rrw++) {  

       for (int cll = 0; cll < 4; cll++) {  

           cout<<"Dept "<<dptcod[rrw]<<" Q"<<(cll+1)<<": ";

           cin>>depts[rrw][cll];  }  }  

       for (int rrw = 0; rrw < 3; rrw++) {  

           int total = 0;

           for (int cll = 0; cll < 4; cll++) {  

               total+=depts[rrw][cll]; }

               cout<<"Dept "<<dptcod[rrw]<<" Total Sales: "<<total<<endl;}  

   return 0; }

Explanation:

This declares the 3 by 4 array which represents the sales of the 3 departments

   int depts[3][4];

This declares a character array which represents the character code of each array

   char dptcod [3] ={'X','Y','Z'};

This iterates through the row of the 2d array

   for (int rrw = 0; rrw < 3; rrw++) {  

This iterates through the column

       for (int cll = 0; cll < 4; cll++) {

This prompts the user for input

           cout<<"Dept "<<dptcod[rrw]<<" Q"<<(cll+1)<<": ";

This gets the input

           cin>>depts[rrw][cll];  }  }  

This iterates through the row of the array

       for (int rrw = 0; rrw < 3; rrw++) {

This initializes total sum to 0

           int total = 0;

This iterates through the column

           for (int cll = 0; cll < 4; cll++) {

This calculates the total sales of each department

               total+=depts[rrw][cll]; }

This prints the total sales of each department

               cout<<"Dept "<<dptcod[rrw]<<" Total Sales: "<<total<<endl;}  

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Exercise1 : Defining Circle type and Creating a Driver Circle class private members double radius double xPos double yPos public
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Answer:

Aee explaination

Explanation:

1) class_circle.h

#include<iostream>

#include<cmath>

#include<iomanip>

#define PI 3.14159

using namespace std;

class circle

{

private:

double radius,xPos,yPos;

public:

double diameter();

double area();

double circumference();

double getRadius();

double getX();

double getY();

void setX(double x);

void setY(double y);

double distanceToOrigin();

bool intersect(const circle& otherCircle);

bool setRadius(double r);

};

class CircleDriver:public circle

{

private:

circle circ1;

circle circ2;

void obtainCircles();

void printCircleInfo();

public:

void run();

};

2) class_circle.cpp

#include "class_circle.h"

double circle::diameter()

{

return (radius * 2);

}

double circle::area()

{

return PI * radius * radius;

}

double circle::circumference()

{

return 2 * PI * radius;

}

double circle::distanceToOrigin()

{

return sqrt((xPos * xPos) + (yPos * yPos));

}

double circle::getRadius()

{

return radius;

}

double circle::getX()

{

return xPos;

}

double circle::getY()

{

return yPos;

}

void circle::setX(double x)

{

xPos = x;

}

void circle::setY(double y)

{

yPos = y;

}

bool circle::setRadius(double r)

{

if(r > 0)

{

radius = r;

return true;

}

else

{

radius = 0;

return false;

}

}

bool circle::intersect(const circle& otherCircle)

{

double dist1 = (radius - otherCircle.radius) * (radius - otherCircle.radius);

double dist2 = ((xPos - otherCircle.xPos) * (xPos - otherCircle.xPos)) + ((yPos - otherCircle.yPos)*(yPos - otherCircle.yPos));

double dist3 = (radius + otherCircle.radius) * (radius + otherCircle.radius);

if((dist1 <= dist2 ) && (dist2 <= dist3) && (dist1 < dist3))

return true;

else

return false;

}

void CircleDriver::obtainCircles()

{

double x,y,rad;

cout<<"Enter xPos yPos circle 1 :";

cin>>x>>y;

do

{

cout<<"\n\nEnter radius for circle 1 :";

cin>>rad;

}while(rad <= 0);

circ1.setX(x);

circ1.setY(y);

circ1.setRadius(rad);

cout<<"\n\nEnter xPos yPos circle 2 :";

cin>>x>>y;

do

{

cout<<"\n\nEnter radius for circle 2 :";

cin>>rad;

}while(rad <= 0);

circ2.setX(x);

circ2.setY(y);

circ2.setRadius(rad);

}

void CircleDriver::printCircleInfo()

{

cout<<setprecision(6)<<endl;

cout<<"\n\nInformation for Circle 1:"<<endl;

cout<<"location:( "<<circ1.getX()<<" ,"<<circ1.getY()<<" )"<<endl;

cout<<"diameter: "<<circ1.diameter()<<endl;

cout<<"area: "<<circ1.area()<<endl;

cout<<"circumference: "<<circ1.circumference()<<endl;

cout<<"distance from the origin: "<<circ1.distanceToOrigin()<<endl;

cout<<"\n\nInformation for Circle 2:"<<endl;

cout<<"location:( "<<circ2.getX()<<" ,"<<circ2.getY()<<" )"<<endl;

cout<<"diameter: "<<circ2.diameter()<<endl;

cout<<"area: "<<circ2.area()<<endl;

cout<<"circumference: "<<circ2.circumference()<<endl;

cout<<"distance from the origin: "<<circ2.distanceToOrigin()<<endl<<endl;

if(circ1.intersect(circ2))

cout<<"The circles intersect."<<endl;

else

cout<<"The circles does not intersect."<<endl;

}

void CircleDriver::run()

{

obtainCircles();

printCircleInfo();

}

3) main.cpp

#include "class_circle.h"

int main()

{

CircleDriver myDriver;

myDriver.run();

return(0);

}

Please refer below output for reference

Enter xPos yPos circle 1 :0.0 50.0

Enter radius for circle 1 :100.0

Enter xPos yPos circle 2 :50.0 0.0

Enter radius for circle 2 :100.0

Information for Circle 1:

location:( 0 ,50 )

diameter: 200

area: 31415.9

circumference: 628.318

distance from the origin: 50

Information for Circle 2:

location:( 50 ,0 )

diameter: 200

area: 31415.9

circumference: 628.318

distance from the origin: 50

The circles intersect.

Process returned 0 (0x0) execution time : 18.245 s

Press any key to continue.

8 0
3 years ago
(Please Help)
strojnjashka [21]

Answer:

C.

Explanation:

An operating system is a route between the software system and hardware system in computers. This program helps to perform actions and execute applications. <u>Functionc performed by an operating system includes process management, handling files, controlling devices such as printers</u>.

The step which is not performed by an operating system while printing a document is that it does not create the document that has to be printed.

While printing, an operating system helps other system know if printer is busy with other operations. Other actions performed by an OS while printing document is that it sends the file, document, or data to be printed to the printer, it connects the computer system with printer.

Thus the correct option is C.

4 0
3 years ago
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