Question

KDS Company has 3 departments: 1. Dept X 2. Dept Y 3. Dept Z. Design a program that will read as input each department's sales for each quarter of the year, and display the result for all divisions.

Answer 1

Complete Question:

Design a program that will use a pair of nested loops to read the company's sales amounts. The details are as follows: -

KDS Company has 3 departments: 1. Dept X 2. Dept Y 3. Dept Z. Design a program that will read as input each department's sales for each quarter of the year and display the result for all divisions. Use a two-dimensional array that will have 3 rows and 4 columns

Answer:

In C++:

#include<iostream>  

using namespace std;  

int main() {  

   int depts[3][4];

   char dptcod [3] ={'X','Y','Z'};

   for (int rrw = 0; rrw < 3; rrw++) {  

       for (int cll = 0; cll < 4; cll++) {  

           cout<<"Dept "<<dptcod[rrw]<<" Q"<<(cll+1)<<": ";

           cin>>depts[rrw][cll];  }  }  

       for (int rrw = 0; rrw < 3; rrw++) {  

           int total = 0;

           for (int cll = 0; cll < 4; cll++) {  

               total+=depts[rrw][cll]; }

               cout<<"Dept "<<dptcod[rrw]<<" Total Sales: "<<total<<endl;}  

   return 0; }

Explanation:

This declares the 3 by 4 array which represents the sales of the 3 departments

   int depts[3][4];

This declares a character array which represents the character code of each array

   char dptcod [3] ={'X','Y','Z'};

This iterates through the row of the 2d array

   for (int rrw = 0; rrw < 3; rrw++) {  

This iterates through the column

       for (int cll = 0; cll < 4; cll++) {

This prompts the user for input

           cout<<"Dept "<<dptcod[rrw]<<" Q"<<(cll+1)<<": ";

This gets the input

           cin>>depts[rrw][cll];  }  }  

This iterates through the row of the array

       for (int rrw = 0; rrw < 3; rrw++) {

This initializes total sum to 0

           int total = 0;

This iterates through the column

           for (int cll = 0; cll < 4; cll++) {

This calculates the total sales of each department

               total+=depts[rrw][cll]; }

This prints the total sales of each department

               cout<<"Dept "<<dptcod[rrw]<<" Total Sales: "<<total<<endl;}