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natita [175]
3 years ago
13

The price of an item has been reduced by 55%. The original price was $53. what is the price now

Mathematics
1 answer:
vichka [17]3 years ago
7 0

Answer:

$29.15

Step-by-step explanation:

Step 1:

$53 × 55%

Step 2:

53 × 0.53

Answer:

29.15

Hope This Helps :)

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Select the postulate of equality or inequality that is illustrated 5 = 5
Oliga [24]

reflexive postulate of equality

7 0
3 years ago
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
2 years ago
PLEASE HELP ASAP FOR 10 POINTS
Olenka [21]

Answer:

The answer is 4m

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
An object is launched from a platform. Its height (in meters), xx seconds after the launch, is modeled by: h(x)=-5(x-4)^2+180 Ho
kozerog [31]

Answer:

x=10

Step-by-step explanation:

h(x)=-5(x-4)^2+180

Set y = 0 to find when it hits the ground

0 = -5(x-4)^2+180

Subtract 180 from each side

-180 =-5(x-4)^2+180-180

-180 =-5(x-4)^2

Divide by -5

-180/-5 =-5/-5(x-4)^2

36 = (x-4)^2

Take the square root of each side

±sqrt(36) = sqrt( (x-4)^2)

±6 =  (x-4)

Add 4  to each side

4±6 =  (x-4)+4

4±6=x

x = 10 or -2

But time cannot be negative so x=10

4 0
3 years ago
Read 2 more answers
Solve: 19.2 x + 3 = 4.6 3x -5
levacccp [35]

Answer:

x=−1.481481

Step-by-step explanation:

Let's solve your equation step-by-step.

19.2x+3=(4.6)(3)x−5

Step 1: Simplify both sides of the equation.

19.2x+3=(4.6)(3)x−5

19.2x+3=13.8x+−5

19.2x+3=13.8x−5

Step 2: Subtract 13.8x from both sides.

19.2x+3−13.8x=13.8x−5−13.8x

5.4x+3=−5

Step 3: Subtract 3 from both sides.

5.4x+3−3=−5−3

5.4x=−8

Step 4: Divide both sides by 5.4.

5.4x

5.4

=

−8

5.4

x=−1.481481

Answer:

x=−1.481481

4 0
3 years ago
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