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Monica [59]
3 years ago
7

Angle 0 lies in the second quadrant, and sin 0=3/5 Cos 0=

Mathematics
1 answer:
borishaifa [10]3 years ago
5 0

Answer:

-4/5

Step-by-step explanation:

Please use a symbol such as x or Ф to represent an angle; your 0 is too easily confused with zero.

If Angle Ф lies in the second quadrant, and sin Ф=3/5, find cos Ф.

The sine of an angle is the ratio of the length of the opposite side to the length of the hypotenuse:  sin Ф = opp / hyp = 3 / 5.  Thus the opp side has length 3 and the hyp has length 5.  By the Pythagorean Theorem,

the adj side has length √(5² - 3²), or √(25-9), or √16, or ±4.  Because the angle is in the 2nd quadrant, choose adj = -4.

Then the cosine of this angle is  cos Ф = adj / hyp = -4 / 5  

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yKpoI14uk [10]

We can't use SAS to prove these triangles are congruent because they're not proportional to two corresponding sides.

<h3>How to illustrate the information?</h3>

It should be noted that the SAS similarity criterion states that when two sides of one triangle are proportional to two corresponding sides of another, and when the included angles are equal, the two triangles are similar.

In this case, we can't use SAS to prove these triangles are congruent because they're not proportional to two corresponding sides.

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brainly.com/question/3999145

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5 0
2 years ago
Quadrilateral RSTQ is a parallelogram.
Ket [755]

Answer:

\angle T \cong \angle R\\\angle S \cong \angle Q

Step-by-step explanation:

According to the Parallelogram definition, every Parallelogram have a pair of congruent sides.  In this case, Namely \overline{RS} \cong \overline{TQ}  and \overline{QR} \cong \overline{TS}

(not listed as an option)

And the opposite angles are congruent too.

So

\angle T \cong \angle R\\\angle S \cong \angle Q

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3 years ago
What is the base of a 36in triangle
ExtremeBDS [4]
Your correct answer is 12.

3 0
3 years ago
Find a unit vector that is orthogonal to both i + j and i + k.
kenny6666 [7]

Answer: i - j - k

Step-by-step explanation:

Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.

<1,1,0> x <1,0,1>

det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )

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What is the strongest relationship you can infer between two variables from this statement?
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Answer:

hope this helps you with your question

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