We can't use SAS to prove these triangles are congruent because they're not proportional to two corresponding sides.
<h3>How to illustrate the information?</h3>
It should be noted that the SAS similarity criterion states that when two sides of one triangle are proportional to two corresponding sides of another, and when the included angles are equal, the two triangles are similar.
In this case, we can't use SAS to prove these triangles are congruent because they're not proportional to two corresponding sides.
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Answer:

Step-by-step explanation:
According to the Parallelogram definition, every Parallelogram have a pair of congruent sides. In this case, Namely
and 
(not listed as an option)
And the opposite angles are congruent too.
So

Your correct answer is 12.
Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
Answer:
hope this helps you with your question