Answer:
Both the parts of this question require the use of the "Intersecting Secant-Tangent Theorem".
Part A
The definition of the Intersecting Secant-Tangent Theorem is:
"If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment."
This, when applied to our case becomes, "The length of the secant RT, times its external segment, ST, equals the square of the tangent segment TU".
Mathematically, it can be written as:
Part B
It is given that RT = 9 in. and ST = 4 in. Thus, it is definitely possible to find the value of the length TU and it can be found using the Intersecting Secant-Tangent Theorem as:
Thus,
Thus the length of TU=6 inches
Answer: the solutions to the system of equations are x = 2 and x = 1
Step-by-step explanation:
The system of equations given equation is
y = 3x - 2 - - - - - - - - - - 1
y = x^2 - - - - - - - - - - - - 2
Substituting 1 into equation 2, it becomes
x^2 = 3x - 2
x^2 - 3x + 2 = 0
We would apply the method of factorization in solving the equation. We will get two numbers such that when added, the result would be - 3x and when multiplied, the result would be 2x^2. The numbers are - 2x and - x. It becomes
x^2 - 2x - x + 2 = 0
x(x - 2) - 1(x - 2) = 0
(x - 2)(x - 1) = 0
x - 2 = 0 or x - 1 = 0
x = 2 or x = 1
.
One solution was found :<span> x = 4</span>
explanation:
From the statement given above, it can be deduced that the measure of the side of the figure is equal to 1 inch. Thus, the scale factor is 1:7. The ratio of their area should be 1:49. To get the area of the smallest figure, we simply divide the given area of the largest figure by 49, giving us the answer which is equal to 12 in². this is all from
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