Step-by-step explanation:
<u>Pattern 1</u> :
Arithmetic Sequence
Common term = 4
<u>Pattern 2</u> :
Geometric Sequence
Common ratio = 2
9. One is 6 over par, the other is three under, so subtract first-second = 6-(-3) = 9
184 x 7 = 1288
7 x 6 = 42
so you have 42 <span>defective bulbs</span>
Answer: What you must do for this case is to graph each of the ordered pairs that you have in the table to obtain the dispersion chart. Note that in your table you have eight ordered pairs, therefore, your scatter chart must have eight pairs.
Step-by-step explanation: