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Vikentia [17]
3 years ago
13

Please help me with this question... I'm confused if the answer is "None of these" OR "Space"...

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0
None of this because you can't answer 8+ 9 or with can't answer 56 <89
You might be interested in
4 x 32 - 3 + 5 x 2 =<br><br> A. 33<br><br> B. 43<br><br> C. 36<br><br> D. 58<br><br> E. 34
DerKrebs [107]

Answer: well according 2 me the answer here is 135

Step-by-step explanation:

but unfortunately you don't have it in your choices

3 0
3 years ago
Suppose the test scores of students in a class are normally distributed with a mean of 85 and a standard deviation of 4. What is
UkoKoshka [18]

Answer:

B

Step-by-step explanation:

Converting it to z, we can use the formula of z-score:

z-score = \frac{x-\mu}{\sigma}

Where

x is the value we are checking for (here, x = 79)

\mu  is the mean, which is 85

\sigma is the standard deviation, which is 4 now

<em>Let's plug the information into the formula and solve for the answer:</em>

<em>\frac{x-\mu}{\sigma}\\\frac{79-85}{4}\\-\frac{6}{4}\\-1.5</em>

<em />

<em>B is the correct answer.</em>

7 0
4 years ago
What is 4 square root 7^3 in exponential form?
Gnesinka [82]

Answer:

Given the radical form: 4\sqrt{7^3}

Use the exponent rules:

\sqrt[n]{a^m} = (a^m)^{\frac{1}{n}} = a^{\frac{m}{n}}

we can write \sqrt{7^3} as:

\sqrt{7^3} = (7^3)^{\frac{1}{2}} = 7^{\frac{3}{2}}

then;

4\sqrt{7^3} = 4 \cdot 7^{\frac{3}{2}}

Therefore, 4\sqrt{7^3} in exponential form is 4 \cdot 7^{\frac{3}{2}}


8 0
3 years ago
Read 2 more answers
Find the area of the trapezoid.
ycow [4]
11 in - 7 in = 4 in
a^2 + (4 in)^2 = (5 in)^2
a^2 + 16 in = 25 in
a^2 = 9 in
a = 3 in
7 in x 3 in = 21 in
1/2( 3 in ) ( 4 in ) = 6 in
a = 21 in + 6 in = 27 in
7 0
3 years ago
Compare the functions below: f(x) = −3 sin(x − π) + 2 g(x) x y 0 8 1 3 2 0 3 −1 4 0 5 3 6 8 h(x) = (x + 7)2 − 1 Which function h
Zinaida [17]
To answer "which function has the smallest minimum," we'll first find the minimum of each one separately.

[1] f(x) = -3 sin(x - pi) + 2. No matter how crazy the inside of a sin function looks, the value of sin itself is always between 1 and -1. So, the minimum value for f(x) is -3*1 + 2 = -1.

[2] g(x). By looking at the table, we see that the minimum value is -1, which occurs when x = 3.

[3] h(x) = (x+7)^2 - 1. Notice that (x+7) is being squared, so the smallest that piece could be is 0 (you can never get a negative number out of (x+7)^2...). So, the minimum value of h(x) is 0 - 1 = -1.

At the end of the day, all three functions have the same minimum value! This can be confirmed on a graph. So, "which function has the smallest minimum value?" all of them!
6 0
3 years ago
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