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djverab [1.8K]
4 years ago
5

HelP MeEe

Mathematics
2 answers:
Delicious77 [7]4 years ago
4 0

Answer:

f(x) = 4(1.02)^(7x); spreads at a rate of approximately 2% daily

omeli [17]4 years ago
3 0

Answer:

f(x) = 4(1.02)^(7x); spreads at a rate of approximately 2% daily

Step-by-step explanation:

The weekly number of people infected is:

f(x) = 4(1.15)^x

So the daily number of people infected is:

f(x) = 4(1+r)^(7x)

To find the value of the daily rate r, we set this equal to the first equation.

4(1.15)^x = 4(1+r)^(7x)

(1.15)^x = (1+r)^(7x)

(1.15)^x = ((1+r)^7)^x

1.15 = (1+r)^7

1.02 = 1+r

r = 0.02

So the equation is f(x) = 4(1.02)^(7x), and the daily rate is approximately 2%.

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I NEED HELP PLEASE !!!!!!
elena-14-01-66 [18.8K]

Answer:

5/6 , - 5/6

Step-by-step explanation:

square root it

6 0
3 years ago
Given: F = {(0, 1), (2, 4), (4, 6), (6, 8)} and G = {(2, 5), (4, 7), (5, 8), (6, 9), (7, 5)} Find the common domain of F and G.
Ann [662]

Answer:

{ 2, 4, 6 }

Step-by-step explanation:

These are the only x values that F and G have in common.

7 0
4 years ago
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I need help in partial fraction!! With simple explaination would be nice!
WITCHER [35]
\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}

Now the second term can be decomposed into partial fractions.

\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}
\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}
4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)
4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1
\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3
\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}

So

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}

3 0
3 years ago
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finlep [7]
The answer is 79 degrees. 
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3 years ago
For what values of x is the inequality x-5≤3 true? a. x≤-2, b. x≤ 8, c. x ≥-2 or d.x≥ 8
damaskus [11]

Answer:

b. x ≤ 8

Step-by-step explanation:

x - 5 ≤ 3

x ≤ 3 + 5

x ≤ 8

8 0
4 years ago
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