We have to calculate the amount of money Peter will have in his account after 5 years. Formula for the amount after t years with interest compounded continuously : A = P * e^(r t ). We know that r = 0.06; t = 5; e = 2.71 and P = $8,000. A = 8,000 * 2.718^( 0.06 * 5 ) = 8,000 * 2,718^( 0.3 ) = 8,000 * 1.3488158 = 10,798.53. Answer:<span> B. $10,798.53. </span>
Put the top point on the first point from the top and the other one on the first point from the bottom.
Given:
The degree of polynomial = 9
Leading coefficient is negative.
To find:
The end behavior of the polynomial.
Solution:
Let the polynomial be P(x).
We have,
Degree of polynomial = 9, which is odd.
Leading coefficient is negative.
If the degree of a polynomial is odd and leading coefficient is negative, then


Therefore, the end behavior of the given polynomial is
.
X=-10 m= 6 that is what I think
Answer c ! Just believe me ik it right