Density = 0.7899 g/mL
mass = 28.7 g
Volume = ?
therefore:
D = m / V
0.7899 = 28.7 / V
V = 28.7 / 0.7899
V = 36.333 mL
<span>Reaction of ethane combustion:
2C2H6 (g) + 7O2 (g) ----> 4CO2 (g) + 6H2O
According to the reaction, we can see that </span>C2H6 and CO2 have following stoichiometric ratio:
n(C2H6) : n(CO2) = 2 : 4
If we know the number of moles of ethane we can calculate moles of carbon dioxide:
2 x n(CO2) = 4 x n(C2H6)
n(CO2) = 2 x n(C2H6)
n(CO2) = 2 x 5.4 = 10.8 mole of CO2 <span>are produced</span>
Atoms will be split into hydrogen and oxygen. A deep blue solution will be formed. Light will be given off. It will create a small explosion.
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