Why do we perform an experiment?

Chemistry

2 answers:

Nesterboy [21]3 years ago

7 0

Answer:

Explanation:

One of its important roles is to test theories and to provide the basis for scientific knowledge that we need to know. How are we supposed to know the answer to our question if we don't perform the experiment to test our question.

7nadin3 [17]3 years ago

6 0

Answer:

Experiment plays many roles in science. One of its important roles is to test theories and to provide the basis for scientific knowledge. It can also call for a new theory, either by showing that an accepted theory is incorrect, or by exhibiting a new phenomenon that is in need of explanation.

Explanation:

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What example of mixture could be seperated using two or more techniques? Explain your answer

STatiana [176]

You can take two liquids of different densities (how much mass is in a given volume) and pour them into a funnel. An example is oil and water. When the mixture settles, the denser liquid will be at the bottom, and drips through the funnel first. This is a separation that you can just let occur naturally.

8 0

3 years ago

Please refer to image please

GarryVolchara [31]

Answer:

76.9L

Explanation:

Based on the graph, whenever the temperature increases by 100K, the volume increases by 10L, so do 769/10

7 0

2 years ago

How many molecules of carbon dioxide are in 5.61 moles of carbon dioxide (CO2)?

gulaghasi [49]

<h3>Answer:</h3>

3.38 × 10²⁴ molecules CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 5.61 moles CO₂

[Solve] molecules CO₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 5.61 \ mooles \ CO_2(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 3.37834 \cdot 10^{24} \ molecules \ CO_2$