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Oksi-84 [34.3K]
3 years ago
5

The half-life of francium-212 is 19 minutes. How many minutes will it take for 100 gram

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
7 0

Answer:

57 mins

Explanation:

From the question given above, the following data were obtained:

Half life (t₁/₂) = 19 mins

Original amount (N₀) = 100 g

Amount remaining (N) = 12.5 g

Time (t) =?

Next, we shall determine the number of half-lives (n) that wound have elapse for 12.5 g of the sample to remain. This can be obtained as follow:

Original amount (N₀) = 100 g

Amount remaining (N) = 12.5 g

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

12.5 = 1/2ⁿ × 100

Cross multiply

12.5 × 2ⁿ = 100

Divide both side by 12.5

2ⁿ = 100 /12.5

2ⁿ = 8

Express 8 index with 2 as the base

2ⁿ = 2³

n = 3

Finally, we shall determine the time taken for 100 g of the isotope to decay to 12.5 g. This can be obtained as follow:

Half life (t₁/₂) = 19 mins

Number of half-lives (n) = 3

Time (t) =?

t = n × t₁/₂

t = 3 × 19

t = 57 mins

Thus, it will take 57 mins 100 g of the isotope to decay to 12.5 g.

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If 45 mL of a 6 M solution is diluted to a final volume of 250 mL, what is concentration of the final solution?
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Answer:

1.08 M

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 45 mL

Initial concentration (C₁) = 6 M

Final volume (V₂) = 250 mL

Final concentration (C₂) =?

The final concentration of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

6 × 45 = C₂ × 250

270 = C₂ × 250

Divide both side by 250

C₂ = 270 / 250

C₂ = 1.08 M

Therefore, the final concentration of the solution is 1.08 M.

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1. A sulfur atom has 16 protons, 18 neutrons, and 16
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Answer:

b. 16 protons, 18 neutrons, and 18 electrons

Explanation:

Things to be remembered

Negative charge on any ionic species indicates gained the electrons

Positive charge on any ionic species indicates lost the electrons

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Balance each of the following in BASE: Show work
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Answer : The balanced chemical equation in a basic solution are,

(A) 2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr(OH)_3+4OH^-+3Cu(OH)_2

(B) 2NO_2+2OH^-\rightarrow NO_3^-+H_2O+NO_2^-

(C) 4Zn+7OH^-+NO_3^-+6H_2O\rightarrow 4[Zn(OH)_4]^{2-}+NH_3

(D) Br_2+12OH^-+5Br_2\rightarrow 2BrO_3^-+6H_2O+10Br^-

Explanation :

<u>(A) The given chemical reaction is :</u>

CrO_4^{2-}(aq)+Cu(s)\rightarrow Cr(OH)_3(s)+Cu(OH)_2(s)

The oxidation-reduction half reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : CrO_4^{2-}+4H_2O+3e^-\rightarrow Cr^{3+}+8OH^-

In order to balance the electrons, we multiply the oxidation reaction by 3 and reduction reaction by 2 then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr^{3+}+16OH^-+3Cu^{2+}

or,

2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr(OH)_3+4OH^-+3Cu(OH)_2

<u>(B) The given chemical reaction is :</u>

NO_2(g)\rightarrow NO_3^-(aq)+NO_2^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : NO_2+2OH^-\rightarrow NO_3^-+H_2O+1e^-

Reduction : NO_2+1e^-\rightarrow NO_2^-

The electrons in both the reactions are balanced. Now added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

2NO_2+2OH^-\rightarrow NO_3^-+H_2O+NO_2^-

<u>(C) The given chemical reaction is :</u>

Zn(s)+NO_3^-(aq)\rightarrow Zn(OH)_4^{2-}(aq)+NH_3(g)

The oxidation-reduction half reaction will be :

Oxidation : Zn+4OH^-\rightarrow [Zn(OH)_4]^{2-}+2e^-

Reduction : NO_3^-+6H_2O+8e^-\rightarrow NH_3+9OH^-

In order to balance the electrons, we multiply the oxidation reaction by 4 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

4Zn+7OH^-+NO_3^-+6H_2O\rightarrow 4[Zn(OH)_4]^{2-}+NH_3

<u>(D) The given chemical reaction is :</u>

Br_2(l)\rightarrow BrO_3^-(aq)+Br^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : Br_2+12OH^-\rightarrow 2BrO_3^-+6H_2O+10e^-

Reduction : Br_2+2e^-\rightarrow 2Br^-

In order to balance the electrons, we multiply the reduction reaction by 5 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

Br_2+12OH^-+5Br_2\rightarrow 2BrO_3^-+6H_2O+10Br^-

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