The two cells of the similar shape, and size have different levels of the ongoing metabolic activity. On one hand, the cell a is metabolically quiet, which means that no energy consuming chemical reactions are taking place in this cell. On the other hand, the cell b is actively consuming the surrounding oxygen. In this scenario, the oxygen will more quickly diffuse into the cell b because the diffusion gradient for oxygen in this cell is steeper than in the cell a.
Hence, the blanks can be filled with 'b and the diffusion gradient is steeper' respectively.
Alyssa's additional observation would be cell Y having a larger vacuole than cell X. The third option is the correct one.
<h3>Plant cell vs animal cell</h3>
From the observations, both cells are eukaryotic. This is because:
- cell X has lysosomes which are only found in eukaryotic cells
- cell Y has a nucleus which also peculiar to eukaryotic cells only
Lysosome houses digestive enzymes and is found mostly in animal cells. Only a few plant cells have lysosomes.
Thus, the lack of a lysosome means that cell Y is a plant cell while the presence means that cell X is an animal cell.
Generally, plant cells have larger vacuoles than animal cells.
More on plant and animal cells can be found here: brainly.com/question/1493437
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Answer:
Null hypothesis: male and female spiders organized in mating pairs don't differ significantly in respect to body length
Alternative hypothesis: male and female spiders organized in mating pairs exhibit significant differences in respect to body length
The application of one statistical test in order to obtain one p-value (probability value) may provide useful evidence to support the alternative hypothesis (or reject it).
The inference procedure uses the information collected from the sample in order to obtain one conclusion. Frequentism is a type of inference procedure that can be used to test a hypothetical test case, which is here represented by male and female spiders organized in mating pairs.
In American Indian so they Thad the highest concentration toxins
1/16
For a dihybrid cross, the ratio is 9:3:3:1, and green and wrinkled is the one so doing the math, that is 1/16
I hope this helps
