8 times 51 show your work

Change the decimal 0.0112 to a fraction

Butoxors [25]

The answer is A. 112/10000

8 0

3 years ago

Read 2 more answers

Help math homework both questions

-Dominant- [34]

Answer:

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Step-by-step explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

<u>Now, According to figure</u>

Sin angle = $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$

Or, Sin Ф = $\dfrac{\textrm x}{\textrm e}$

Or, Sin 45° = $\dfrac{\textrm x meters}{\textrm 1.2 meters}$

Or, 0.707 × 1.2 meters = x

∴ x = 0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters . Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend = Ф = 22°

Let the glide runway path = y feet

<u>Now, According to question</u>

Tan angle = $\dfrac{\textrm perpendicular}{\textrm base}$

Or, Tan Ф = $\dfrac{\textrm H}{\textrm y}$

Or, Tan 22° = $\dfrac{\textrm 10,000 feet}{\textrm y feet}$

Or, 0.4040 = $\dfrac{\textrm 10,000 feet}{\textrm y feet}$

Or, y = $\dfrac{\textrm 10,000 feet}{\textrm 0.4040}$

∴ y = 24,752.47

So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer

6 0

3 years ago

if Michael had four oranges and Timmy had 5 oranges and they combined them together how many oranges do they have in total

bija089 [108]

They have 9 because
$5 + 4 = 9$

4 0

3 years ago

Read 2 more answers

**PLEASE HELP**

zepelin [54]

----------------------------------------------------------
Given information
----------------------------------------------------------
Area = 3x² + 14x + 8
Length = x + 4

----------------------------------------------------------
Formula
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Area = Length x Width

----------------------------------------------------------
Find Width
----------------------------------------------------------
3x² + 14x + 8 = (x + 4) x width
width = (3x² + 14x + 8) ÷ (x + 4)
width = (x+4)(3x+2) ÷ (x + 4)
width = 3x + 2

----------------------------------------------------------
Answer: The width is 3x + 2 (Answer C)
----------------------------------------------------------

5 0

4 years ago

Line segment 19 units long running from (x,0) ti (0, y) show the area of the triangle enclosed by the segment is largest when x=

Debora [2.8K]

The area of the triangle is

A = (xy)/2

Also,

sqrt(x^2 + y^2) = 19

We solve this for y.

x^2 + y^2 = 361

y^2 = 361 - x^2

y = sqrt(361 - x^2)

Now we substitute this expression for y in the area equation.

A = (1/2)(x)(sqrt(361 - x^2))

A = (1/2)(x)(361 - x^2)^(1/2)

We take the derivative of A with respect to x.

dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]

dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]

Now we set the derivative equal to zero.

(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0

-2x^2 + 361 = 0

-2x^2 = -361

2x^2 = 361

x^2 = 361/2

x = 19/sqrt(2)

x^2 + y^2 = 361

(19/sqrt(2))^2 + y^2 = 361

361/2 + y^2 = 361

y^2 = 361/2

y = 19/sqrt(2)

We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.

3 0

3 years ago