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Oduvanchick [21]
3 years ago
11

A barrel in Jim's yard contains 60 gallons of water. Water leaks out of the barrel at a rate of 1 gallon every 10 minutes. Creat

e and graph the solution set of the equation for the gallons of water, y, remaining in the barrel in terms of the number of minutes elapsed, x.

Mathematics
2 answers:
emmainna [20.7K]3 years ago
7 0

Answer:

y=-0.10x+60

Step-by-step explanation:

Let

y -----> gallons of water remaining in the barrel

x-----> number of minutes elapsed

we know that

Water leaks out of the barrel at a rate of 1 gallon every 10 minutes

so

1/10=0.10\frac{gal}{min}

The linear equation that represent this situation is  

y=-0.10x+60

The graph in the attached figure

Bad White [126]3 years ago
5 0

Answer:

So you t   start with 60 because that is how many gallons Jim has. Then you can count by tens until you get to 100. it takes 10 tens to get to 100 which means that for each 10 mins 1 gallon is lost. so the number of gallons lost in 100 mins is 10. so the point would read (100, 50) for every hundred mins, 10 gallons of water are lost. nUntil you hit zero because  cannot have negative amounts of water. Even s helps!

Step-by-step explanation:

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Then the equation is:

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Step-by-step explanation:

Ok, let's solve this.

We know that water is drained from a reservoir, let's assume that we can model this situation with a linear relation:

y = a*x + b

Where x is time, y is the height of the water in the reservoir, a is the slope (in this case represents how much changes the height of the water in the reservoir in one unit of time) and b is the initial height of the water in the reservoir.

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For this particular case we know that after 2 minutes the height of the water is 175 ft, then we have the point (2 min, 175 ft)

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205 ft = b

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y = (-15 ft/min)*x + 205 ft

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