Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
please mark me the brainiest
You have to have the same unit of measure. Here your units are "minutes" and "seconds". In order to compare the two, you must change to 240 seconds into minutes (dividing by 60 = 4 mins) OR change the 5 minutes into seconds (multiply by 60 to give you 300 seconds)
So for eliminating, you only solve for one variable first.
I solved for y, so I multiplied by -4 to eliminate the x.
Then I got y= -1
I then substituted that to one of the equations to get x.
The correct choice would be 128.
If there are 6 options and the person can pick any number of toppings, we need to know the number of subsets that can be formed with 6. That would be 2^6 or 64.
Since there is a pan or hand-tossed option, we need to multiply 64 by 2 to find the total.
64 x 2 = 128
Answer:
6:21
Step-by-step explanation:
because there is 6 roses and 21 other types 6/21 = 6:21
