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klemol [59]
3 years ago
5

rose rode the roller coaster 9 times. Leila rode the roller 6 less times than Rose. Joseph rose roller coaster 5 times as many a

s Leila. how many times did Joseph ride the roller coaster?
Mathematics
2 answers:
Paha777 [63]3 years ago
8 0
Joseph rode the roller coaster 15 times.
Because - 9 - 6 = 3 x 5 = 15
pshichka [43]3 years ago
3 0
He rode the roller coaster 15 times because 9-6=3 and 3×5=15.
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What will the equation be if mowing need help. I need my lawn mowed every week from June through the middle of July. I will pay
sergij07 [2.7K]
So for the first week of june, say week 1, you have to pay then 35(1), 2nd week is 35(2), week 3 is 35(3) and week "w" say, is 35(w).

\bf \stackrel{payment}{p}=35\stackrel{weeks}{w}\implies p=35w\qquad 1\le x\le 7
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Evaluate if a = 28 and b = -3
Nata [24]

Answer:

The answer is 4

Step-by-step explanation:

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8 0
3 years ago
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Alexis has 32 2/5 ounces of beads. How many necklaces can she make if each uses 2 7/10 ounces of beads?
love history [14]
32 2/5 ÷ 2 7/10 let's turn above into improper fractions: 32 2/5 ----> 162/5 2 7/10 -----> 27/10 so, 162/5 ÷ 27/10 -------> 162/5 * 10/27 = 12 necklaces
6 0
3 years ago
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Please help top and bottom.
Helga [31]
1. Perimeter
22a + 2(6a + 8) -4 = p

[I got 22a from 12a + 10a]

2. If p = 250, what is a?

22a + 2(6a + 8) - 4 = 250
Distributive property
22a + 12a + 16 - 4 = 250
Add like terms
34a + 12 = 250
Subtract 12 by both sides
34a = 238
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3 0
3 years ago
a regular rectangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface ar
Margarita [4]
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)

Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.

The lateral faces are equilateral triangles of side length x.

The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18  cm^2.

now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.

by the Pythagorean theorem: 

h= \sqrt{ x^{2} - (x/2)^{2}}= \sqrt{ x^{2}- x^{2}/4}= \sqrt{3x^2/4}= \frac{ \sqrt{3} }{2}x

thus, 

Area_{triangle}= \frac{1}{2}\cdot base \cdot height\\\\18= \frac{1}{2}\cdot x \cdot \frac{ \sqrt{3} }{2}x\\\\ \frac{18 \cdot 4}{ \sqrt{3}}=x^2

thus:

x^2 =\frac{18 \cdot 4}{ \sqrt{3}}= \frac{18 \cdot 4 \cdot\  \sqrt{3} }{3}=24 \sqrt{3}       (cm^2)

but x^{2} is exactly the base area, since the base is a square of sidelength = x cm.


So, the total surface area = base area + lateral area =  24 \sqrt{3}+72   cm^2


Answer: 24 \sqrt{3}+72   cm^2

4 0
3 years ago
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