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3 years ago

Write an equation in standard form for:

1 answer:

5 0

Hello!
When finding the perimeter of a rectangle, you have to consider the properties of a rectangle. A rectangle has two pairs of equal sides where one is the width, while the other one is the length.
Now looking back at your question, it says "... a rectangle that is x units wide" ⇒ you let the width = x ; this is the same with "y units long" ⇒ length = y. Perimeter can just be : P = 24.
Therefore,
The equation would be:
x + x + y + y = P.
2x + 2y = P.
(Sub in P = 24)
∴ 2x + 2y = 24. (This should be your answer.)
:) Good luck (Message me if you have any problem)

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Which function is equivalent to the inverse of y=sec(x)

kipiarov [429]

From the identity:

$sec(x)= \frac{1}{cos(x)}$

$f(x)=sec(x)= \frac{1}{cos(x)}$

the inverse of f is g such that f(g(x))=x,

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thus, $cos[g(x)]= \frac{1}{x}$

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4 years ago

Jaun's age, x, is 4 times his age 15 years ago

KIM [24]

The expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

<h3>How to rewrite the statement as an expression?</h3>

The mathematical statement is given as

Jaun's age, x, is 4 times his age 15 years ago

From the statement, we have:

x represent Juan's current age

This means that his age 15 years ago is

15 years ago = x - 15

4 times his age 15 years ago is

4 * 15 years ago = 4 * (x - 15)

The above equation is equivalent to his current age

So, we have

x = 4 * (x - 15)

Hence, the expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

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1 year ago

A function is given. Determine the average rate of change of the function between the given values of the variable: f(x)= 4x^2;

nevsk [136]

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------$

$\bf f(x)= 4x^2 \qquad 
\begin{cases}
x_1=3\\
x_2=3+h
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\\\\\\
\cfrac{[4(3+h)^2]~~-~~[4(3)^2]}{\underline{3}+h-\underline{3}}\implies \cfrac{4(3^2+6h+h^2)~~-~~4(9)}{h}
\\\\\\
\cfrac{4(9+6h+h^2)~~-~~36}{h}\implies \cfrac{\underline{36}+24h+4h^2~~\underline{-~~36}}{h}
\\\\\\
\cfrac{24h+4h^2}{h}\implies \cfrac{\underline{h}(24+4h)}{\underline{h}}\implies 24+4h$

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3 years ago

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3 years ago

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Ymorist [56]

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3 years ago