Please help me with this question!

Tyler's mom purchased a savings bond for Tyler. The value of the savings bond increases by 4% each year. One year after it was p

Alla [95]

Answer:

150

Step-by-step explanation:

Since the value of the bond increases by 4% each year and only 1 year passed by then the ROI is not compounded and we only need to find the value before the 4% was implemented. In order to add 4% to a value we would multiply that value by 1.04 which increases that value by 4%. So, to find the value before the interest was added we would need to divide the new value by 1.04 instead.

$156 / 1.04 = $150

Finally, we can see that the value of the bond when Tyler's mom purchased it was 150

6 0

3 years ago

Solve for X. round to the nearest tenth. 2 5 x 3.5

notka56 [123]

I would say 2.....sorry if I am wrong

6 0

3 years ago

(URGENT!!!) Can someone help me with this? For part a), would the equation A=200(15)^m=395 work? In part b), can't I just factor

Levart [38]

A.) 200+15m=395. This is because the initial price is 200, and after that she will add $15/month. The equation you chose would be exponential, meaning the rate would increase as time passed, which is not the case. Instead, the rate is constant, and the only think that changes is m, the number of months.

b.) I believe it will be easier to answer with ^this equation.

c.) The rate of change would be 15, since the rate is increasing monthly by $15.

d.) Once you solve 209+15m=495, you'll have the answer.

7 0

3 years ago

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

3 years ago

Name the property of real numbers illustrated by the equation.

Julli [10]

Answer:

Distributive property

Step-by-step explanation:

The distributive property states a(b+c)=a*b+a*c. This property states that when you multiply more than one thing, you must be sure to multiply everything. When you order fast food combos, you do the distribution property to receive the correct order.

If I order 3 Happy Meals, then I will receive

3(hamburgers +fries + drinks +toys)

3 hamburgers+3 fries+3 drinks+3 toys.

If I don't, then I have broken the distribution property.

5 0

3 years ago