Answer : The percent by mass of water the salt contain is, 55.3 %
Explanation : Given,
Mass of hydrated salt = 12.10 g
Mass of salt = 5.41 g
First we have to calculate the mass of water.
Mass of water = Mass of hydrate salt - Mass of salt
Mass of water = 12.10 g - 5.41 g
Mass of water = 6.69 g
Now we have to calculate the percent by mass of water the salt contain.
Now put all the given values in this expression, we get:
Therefore, the percent by mass of water the salt contain is, 55.3 %
Answer:
1.7927 mL
Explanation:
The mass of solid taken = 4.75 g
This solid contains 21.6 wt% , thus,
Mass of =
= 1.026 g
Molar mass of = 261.337 g/mol
The formula for the calculation of moles is shown below:
Thus,
Considering the reaction as:
1 moles of react with 1 mole of
Thus,
0.003926 mole of react with 0.003926 mole of
Moles of = 0.003926 mole
Also, considering:
Molarity = 2.19 M
So,
Volume = 0.0017927 L
Also, 1 L = 1000 mL
<u>So, volume = 1.7927 mL</u>