Answer:
15th term =29/3
16th term = 31/3
Step-by-step explanation:
Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d .
First we find the 15th term
n=15
a1=1/3
d=1 - 1/3 = 2/3
Solution
1/3+(15-1)2/3
1/3+28/3
(1+28)/3
29/3
Lets find the 16th term
1/3+(16-1)2/3
1/3+30/3
(1+30)/3
31/3
P = $2000, Rate, r = 6% = 0.06 per year, Time, t = 5 years.
For compound interest compounded annually:
A) Amount, A = P(1 + r)^t
A = 2000(1 + 0.06)⁵
A = 2000(1.06)⁵ ≈ 2676.45
Amount ≈ $2676.45
<span>B) Interest = Amount - Principal </span>
= 2676.45 - 2000 = 676.45
<span>Interest ≈ $676.45<span> </span></span>
The answer is C. This would only be displayed on a one bar graph.
Answer with Step-by-step explanation:
We are given that an equivalence relation P on Z as
Let 
if and only if
such that x-y=2k.
We have to show that how the reflexive property and symmetric property of an equivalence relations hold for P on Z.
We know that reflexive property
a is related to a by given relations.
If xPax then we get

Where k=0 and 0 belongs to integers.
Hence, the relation satisfied reflexive property.
Symmetric property :If a is related to b then b is related to b.
If x and y is related by the relation
where k is any integer

k belongs to integers.
Hence, relation satisfied symmetric property.