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sveticcg [70]
3 years ago
14

Two 6-sided dice are rolled. what is the probability that the sum of the two numbers on the dice will be greater than 8?

Mathematics
1 answer:
Serhud [2]3 years ago
6 0

Answer: 5/18

Step-by-step explanation:

The sample space when two 6- sided dice are rolled is given below:

(+) 1 2 3 4 5 6

1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11  12

The total sample space is 36.

Sum greater than 8 are : {9,10,11,12}

which are 10 in number:

Therefore : the probability that the sum of the two numbers on the dice will be greater than 8 will be :

number of the sum greater than 8 / Total sample space

That is ;

P(sum greater than 8) = 10/36

P(sum greater than 8) = 5/18

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
What is the exterior angle of triangle ABC<br><br> These are the points:<br> A=3, B=10, C=6
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A coin contains 1.25 grams of nickel and 3.75 grams of copper, for a total weight of 5 grams what percentage of the metal in coi
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7 0
4 years ago
Read 2 more answers
Bryan’s monthly electric bill is determined by adding a flat administration fee to the product of the number of kilowatt hours o
Sophie [7]
We will form the equations for this problem:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
z = ? Monthly administration fee is notated with z, and that is the this problem's question.
Number of kilowatt hours of electricity used are numbers 1100 and 1500 respectively.
Cost per kilowatt hour is notated with y, but its value is not asked in this math problem, but we can calculate it anyway.
The problem becomes two equations with two unknowns, it is a system, and can be solved with method of replacement:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
----------------------------
(1) z = 113 - 1100*y [insert value of z (right side) into (2) equation instead of z]:
(2) 1500*y + (113 - 1100*y) = 153
-------------------------------------------------
(1) z = 113 - 1100*y
(2) 1500*y + 113 - 1100*y = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y + 113 = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 153 - 113
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 40
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 40/400
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 1/10
------------------------------------------------
if we insert the obtained value of y into (1) equation, we get the value of z:
(1) z = 113 - 1100*(1/10)
(1) z = 113 - 110
(1) z = 3 dollars is the monthly fee.
6 0
3 years ago
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umka2103 [35]
Hopefully I get this right I’m pretty sure it’s C
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