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Lapatulllka [165]
2 years ago
14

Round your answer to the nearest hundredth.

Mathematics
1 answer:
nika2105 [10]2 years ago
5 0

Answer:

5.52umit

sin65  =  \frac{ac}{ab}  =  \frac{5}{ab}  \\ ab =  \frac{5}{sin65}  = 5.52 \\ ab = 5.52umit

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There are 42 citizens called for jury duty. Eleven are randomly chosen to for the interview phase. How many different ways can t
Sunny_sXe [5.5K]

The quick way to get the answer is just type "42 choose 11" into Google.

Or if you want to figure it out yourself, you have 42 choices for the first potential juror, 41 choices for the second potential juror, etc.

Now before you stop there, you only care about the combination of the 11 people chosen, not what order they are selected, so you need to divide by the ways to arrange 11 people.

Final expression:

C(42,11) = (42 * 41 * 40 * 39 * 38 * 37 * 36 * 35 * 34 * 33 * 32) / (11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)

Answers:

4,280,561,376 ways

4 0
3 years ago
Read 2 more answers
In a trivia game, you lose points for incorrect answer. You answer the first 3 questions wrongs. Your score after the 3 question
Ksivusya [100]
Each incorrect answer is 25 points
5 0
3 years ago
I REALLY NEED HELP PLEASE HELP ME :(
o-na [289]

Answer:

I may be wrong but I think 8 is your answer.

Step-by-step explanation:

(-1)^(3/7)  x 128^(3/7)

-1 x 128^3/7

128^(3/7) = 8

= 8

6 0
3 years ago
Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = 3 (*sqaure root sign*) t (20 − t), [0,
mafiozo [28]

9514 1404 393

Answer:

  • maximum: 15∛5 ≈ 25.6496392002
  • minimum: 0

Step-by-step explanation:

The minimum will be found at the ends of the interval, where f(t) = 0.

The maximum is found in the middle of the interval, where f'(t) = 0.

  f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)

This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...

  f(5) = (∛5)(20-5) = 15∛5

The absolute maximum on the interval is 15∛5 at t=5.

5 0
3 years ago
3.Find the area of Triangle and Parallelogram having base 13.5cm and height is 18cm.​
patriot [66]
  • Base=13.5cm
  • Height=18cm

\\ \sf\longmapsto Area=\dfrac{1}{2}Base\times Height

\\ \sf\longmapsto Area=\dfrac{1}{2}(18)(13.5)

\\ \sf\longmapsto Area=9(13.5)

\\ \sf\longmapsto Area=121.5cm^2

3 0
2 years ago
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