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Lapatulllka [165]

2 years ago

14

Round your answer to the nearest hundredth.

1 answer:

nika2105 [10]2 years ago

5 0

Answer:

5.52umit

$sin65 = \frac{ac}{ab} = \frac{5}{ab} \\ ab = \frac{5}{sin65} = 5.52 \\ ab = 5.52umit$

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I need help on these two questions

alisha [4.7K]

Answer:

A) The answer is a to the second power

B) The answer is c to the first power or you can just write c

Step-by-step explanation:

If there are exponents that have the same base and you are dividing, you will need to subtract the exponents.

A)5-3=2

The answer is a to the second power

B) 4-3=1

The answer is c to the first power or you can just write c

Hope this helps!

4 0

2 years ago

Read 2 more answers

Can someone help me I’m stuck on how to do this

Aleksandr [31]

Answer:

Step-by-step explanation:

7 0

3 years ago

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

2 years ago

Linda's account has a balance of −$45.50. If she owes the bank more than $30, her account gets closed. Which of the following is

Gwar [14]

Can you attach the multiple choices please

3 0

2 years ago

The perimeter of a triangle is 38cm. The first side is 10cm longer than the second side, the third side is twice as long as the

Natalija [7]

Side 1: 17 Cm.
Side 2: 7 Cm.
Side 3: 14 Cm.

Hope This Helped.

8 0

2 years ago