<span>the study of living organisms, divided into many specialized fields that cover their morphology, physiology, anatomy, behavior, origin, and distribution.</span>
A
Bronsted-Lowry acid is a proton donor (usually hydrogen ion). And a
Bronsted-Lowry base is a proton acceptor (usually hydrogen ion). Consider a
chemical reaction between HCl and NaOH. We have the reaction HCl + NaOH à NaCl + H2O. The
hydroxide ions in the NaOH are bases because they accept hydrogen ions from
acids to form water. And an acid produces hydrogen ions in solution by giving a
proton to the water molecule. Therefore, the answer is d. a Bronsted-Lowry
base.
<u>Answer:</u> The value of 
for the given chemical equation is 0.0457.
<u>Explanation:</u>
Given values:
Initial moles of 
= 0.700 moles
Volume of conatiner = 3.50 L
The given chemical equation follows:
I: 0.700
C: -2x +2x x
E: 0.700-2x 2x x
Equilibrium moles of 
= x = 0.180 moles
Equilibrium moles of 
= 2x = 
Equilibrium moles of = 0.700 - 2x = 
Molarity is calculated by using the equation:
So,
![[SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M](https://tex.z-dn.net/?f=%5BSO_3%5D_%7Beq%7D%3D%5Cfrac%7B0.340%7D%7B3.50%7D%3D0.0971M)
![[SO_2]_{eq}=\frac{0.360}{3.50}=0.103M](https://tex.z-dn.net/?f=%5BSO_2%5D_%7Beq%7D%3D%5Cfrac%7B0.360%7D%7B3.50%7D%3D0.103M)
![[O_2]_{eq}=\frac{0.180}{3.50}=0.0514M](https://tex.z-dn.net/?f=%5BO_2%5D_%7Beq%7D%3D%5Cfrac%7B0.180%7D%7B3.50%7D%3D0.0514M)
The expression of for above equation follows:
![K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BSO_2%5D%5E2%5BO_2%5D%7D%7B%5BSO_3%5D%5E2%7D)
Plugging values in above expression:
Hence, the value of for the given chemical equation is 0.0457.
<span>Every organism needs the energy to carry out a number of different processes, such as growth and reproduction. The energy is necessary for different metabolic processes and reactions inside the cells. Plants do not move around, so they don't need energy for movement, but they need the energy to develop, to grow, to produce food, to reproduce, and many other processes.</span>
