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Art [367]
3 years ago
6

Match each decimal number to the correct scientific notation.

Chemistry
2 answers:
Effectus [21]3 years ago
5 0

3.07 × 10^4=30,700

3.07 × 10^-4=0.000307

3.07 × 10^-6=0.00000307

3.07 × 10^6=3,070,000



GREYUIT [131]3 years ago
4 0

Answers are:

3.07 × 10^4 = 30,700.

3.07 × 10^-4 = 0.000307.

3.07 × 10^-6 = 0.00000307.

3.07 × 10^6 = 3,070,000.

1) 10^4 = 10 × 10 × 10 × 10.

10^4 = 10,000.

3.07 × 10^4 = 3.07 × 10,000.

3.07 × 10^4 = 30,700.

2) 10^-4 = 1 ÷ (10 × 10 × 10 × 10).

10^-4 = 1 ÷ 10,000.

10^-4 = 0.0001.

3.07 × 10^-4 = 3.07 × 0.0001.

3.07 × 10^-4 = 0.000307.

3) 10^-6 = 1 ÷ (10 × 10 × 10 × 10 × 10 × 10).

10^-6 = 1 ÷ 1,000,000.

10^-6 = 0.000001.

3.07 × 10^-6 = 3.07 × 0.000001.

3.07 × 10^-6 = 0.00000307.

4) 10^6 = 10 × 10 × 10 × 10 × 10 × 10.

10^6 = 1,000,000.

3.07 × 10^6 = 3.07 × 1,000,000.

3.07 × 10^6 = 3,070,000.

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What is the volume of 33.25g of butane gas at 293 C and 10.934 kPa?
PSYCHO15rus [73]

Answer:

V = 240.79 L

Explanation:

Given data:

Volume of butane = ?

Temperature = 293°C

Pressure = 10.934 Kpa

Mass of butane = 33.25 g

Solution:

Number of moles of butane:

Number of moles = mass/ molar mass

Number of moles = 33.25 g/ 58.12 g/mol

Number of mole s= 0.57 mol

Now we will convert the temperature and pressure units.

293 +273 = 566 K

Pressure = 10.934/101 = 0.11 atm

Volume of butane:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

V = nRT/P

V = 0.57 mol × 0.0821 atm.L/ mol.K  ×566 K  / 0.11 atm

V = 26.49 L/0.11

V = 240.79 L

6 0
3 years ago
If 0.959J of heat is added to 0.88g of water, how much will its temperature increase
ss7ja [257]

Answer:

0.260 Celsius

Explanation:

q =c x m x (T2-T1)

c - specific heat of water 4.186 J/g.C

T2-T1 = q /(c x m) = 0.959 /(4.186 x 0.88) = 0.959/3.68 =0.260 C

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3 years ago
Given that the free energy of the twist-boat conformer of cyclohexane is 5.3 kcal/mol greater than that of the chair conformer,
marishachu [46]

Answer:

0.013%

Yes, it does. The answer agrees with the statement.

Explanation:

Both conformers are in equilibrium, and it can be represented by the equilibrium equation K:

K = [twist-boat]/[chair]

The free energy between them can be calculated by:

ΔG° = -RTlnK

Where R is the gas constant (8.314 J/mol.K), and T is the temperature (25°C + 273 = 298 K).

ΔG° = 5.3 kcal/mol * 4.182 kJ/kcal = 22.165 kJ/mol = 22165 J/mol

22165 = -8.314*298*lnK

-2477.572lnK = 22165

lnK = -8.946

K = e^{-8.946}

K = 1.30x10⁻⁴

[twist-boat]/[chair] = 1.30x10⁻⁴

[twist-boat] = 1.30x10⁻⁴[chair]

The percentage of the twist-boat conformer is:

[twist-boat]/([twist-boat] + [chair]) * 100%

1.30x10⁻⁴[chair]/(1.30x10⁻⁴[chair] + [chair]) *100%

0.013%

The statement about the conformers is that the chair conformer is more stable, and because of that is more present. So, the answer agrees with it.

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