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VLD [36.1K]
3 years ago
8

Water(H20) is not found on the Periodic Table of the elements because water is​

Chemistry
2 answers:
olya-2409 [2.1K]3 years ago
7 0

Water is not found on the periodic table because it does not consist of a single element.

ziro4ka [17]3 years ago
7 0

Answer:

its made up of two elements thats why its is not in the periodic table

Explanation:

table is called periodic table of elements

not compounds

dumb

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WILL GIVE BRAINLIEST AND POINTS!!
Aleksandr [31]

Answer:

H2O= +2

CCl4 = +4

Na+= 0

CuCl2= -2

5 0
3 years ago
What are the main method of combination?<br><br>​
Pepsi [2]

Explanation:

Each atom type contains the same number of protons. Chemical bonds link elements together to form more complex molecules called compounds. A compound consists of two or more types of elements held together by covalent or ionic bonds

7 0
3 years ago
Calcium carbonate decomposes at high temperatures to give calcium oxide and carbon dioxide as shown below. CaCO3(s) CaO(s) + CO2
romanna [79]

Answer:

\boxed{\text{10.0 g}}

Explanation:

The balanced equation is

CaCO₃(s) ⇌ CaO(s) + CO₂(g); Kp = 1.16

Calculate Kc

T= 800 °C = 1073 K; Δn= 1

K_{\text{p}} = K_{\text{c}}{RT}^{\Delta n}\\\\1.1 = K_{c}{(RT)}^{1}\\\\K_{c} = \dfrac{1.1}{RT} = \dfrac{1.1}{8.314\times 1073}= \dfrac{1.1}{8921} = 1.233 \times 10^{-4}

Equilibrium concentration of CO₂

K_{c} = [\text{CO}_{2}] = 1.233 \times 10^{-4}

Moles of CO₂ formed

n= \text{5.00 L } \times \dfrac{\text{1.233 $\times$ 10$^{-4}$ \text{ mol} }}{\text{1 L}} = 6.155 \times 10^{-4}\text{ mol}

Moles of CaCO₃ used up

Moles of CaCO₃ used up = moles of CO₂ formed = 6.155 × 10⁻⁴ mol

Mass of CaCO₃ used up

m = 6.155 \times 10^{-4}\text{ mol } \times \dfrac{\text{100.09 g}}{\text{1 mol}} = \text{0.0616 g}

Moles of CaO formed

Moles of CaO formed = moles of CO₂ formed = 6.155 × 10⁻⁴ mol

Mass of CaO formed

m = 6.155 \times 10^{-4}\text{ mol } \times \dfrac{\text{56.08 g}}{\text{1 mol}} = \text{0.0345 g}

Mass of solid at equilibrium

m = 10.0 g – 0.0616 g + 0.0345 g = 10.0 g

\text{The mass of solid remaining at equilibrium is } \boxed{\textbf{10.0 g}}

6 0
3 years ago
Show workk!!! pls
Dimas [21]

Answer:

2.2moles

Explanation:

Given parameters:

Atomic mass of Radium = 226

Mass of Radium  = 497.2g

Unknown:

Number of moles  = ?

Solution:

To solve this problem, we use the expression below:

    Number of moles  = \frac{mass}{molar mass}

The molar mass of the radium   = 226g/mol

So;

       Number of moles  = \frac{497.2}{226}   = 2.2moles

6 0
3 years ago
Which of these would DECREASE the solubility of a solid in water?
stepladder [879]

Answer: B) Increasing the air pressure

Explanation:

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