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Karolina [17]
3 years ago
11

Plants don't move around, so why do they need energy?

Chemistry
1 answer:
kifflom [539]3 years ago
3 0
<span>Every organism needs the energy to carry out a number of different processes, such as growth and reproduction. The energy is necessary for different metabolic processes and reactions inside the cells. Plants do not move around, so they don't need energy for movement, but they need the energy to develop, to grow, to produce food, to reproduce, and many other processes.</span>
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*30 points* Pls answer following the rules of :No files
gladu [14]
<h3>1.Option B</h3><h3>Elements can be defined as pure substances that are made up of only single type of atom. </h3>

<h2>Note:</h2>

  • Single type of atom not single atom

<h3>2.Option B </h3><h3>Aluminum foil is correct because heterogenous mixtures are uniform throughout the mixture. and foil is uniform but other option given are not uniform.</h3>
4 0
3 years ago
Explique las diferencias entre mezcla y combinación. De un ejemplo de cada uno.
Brums [2.3K]

Answer:

He means Explain the differences between mix and match. Give one example of each.

Explanation:

3 0
3 years ago
If the hydrogen ion concentration is 10-7M, what is the pH of the solution?<br><br> Show all work.
Kobotan [32]
Remember pH=-log(H ions). So it would be pH=-log(10^-7).
6 0
4 years ago
1. 10.0 g of CaCO 3 ​ on heating gave 4.4 g of CO 2 ​ and 5.6 g of CaO. The observation is in agreement with the law of conserva
finlep [7]

Answer:

  1. According to the law <br> Mass of reactants = mass of product, here <br> `underset(10 g)(CaCO_(3))rarr underset(4.4 g)(CO_(2))+underset(x)(CaO)` <br> Hence, x = 10 g - 4.4 g = 5.6 g <br> Which is mass of CaO.d
  2. In the first compound <br> Hydrogen = 5.93 % <br> Oxygen = `(100-5.93)% = 94.07 %` <br> In the second compound <br> Hydrogen = 11.2 % <br> Oxygen `= (100-11.2)%=88.8%` <br> In the first compound the number of parts by mass of oxygen that combine with one part by mass of hydrogen `=(94.07)/(5.93)=15.86` parts ...
  3. (The ratio of Cu combining with fixed weight of oxygen in black and red oxide is 1 : 2 respectively. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.) {Check something more in the above attachment!}
  4. Refer to the above attachment

Explanation:

<em>Mark </em><em>this </em><em>answer </em><em>as </em><em>brainlest </em><em>answer</em><em>!</em><em>!</em>

5 0
2 years ago
A food processing plant discharges 40 cfs (cubic feet per second) of process water containing an ultimate BOD (L0) of 25 mg/L an
Feliz [49]

Answer:

The right solution according to the question is provided below.

Explanation:

According to the question,

(a)

The initial conditions will be:

DO = \frac{(40\times 1.8)+(260\times 7.6)}{40+260}

      = \frac{2048}{300}

      = 6.826 \ mg/L

The initial oxygen defict will be:

Do = 8.5-6.826

     = 1.674 \ mg/L

The initial BOD will be:

Lo = \frac{(40\times 25)+(260\times 3.6)}{40+260}

    = \frac{1936}{300}

    = 6.453 \ mg/L

(b)

The time reach minimum DO:

tc = \frac{1}{(kr-kd)} ln{(\frac{0.76}{0.61} )[1-\frac{1.674(0.76-0.61)}{0.61\times 6.453} ]}

   = \frac{1}{0.15}\times ln \ 1.158

By putting the values of log, we get

   = 0.973 \ days

The distance to reach minimum DO will be:

Xc = \frac{1.1\times 3600\times 24}{5280}\times 0.973 \ days

    = 18\times 0.973

    = 17.5 \ miles

8 0
3 years ago
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