There are 12 marbles in total in the bowl.
From this bowl, we will choose 4 marbles at random.
That's 12C4 or (12*11*10*9) or 11,880 ways
Out of this, what is the probability that there is exactly 1 blue marble.
There are 5 blue balls but only 1 is selected, 5C1 ways
The rest except blue calls are 7, but only 3 slots are left, 7C3 ways
The probably of exactly 1 blue of 4 marbles is then 5C1*7C3/12C4 = 1050/11,880 = 0.0884 or 8.84%
Hope this helps:) would appericate brainliest thanks
Answer:
y=4x
Step-by-step explanation:
it goes through 0,0 on my graph
Answer:
a= ft is the unit
b=g(gram) is the unit
c= percent % is the answer
Answer:
By simplifying the expression we get
4/3
