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3 years ago

6

Evaluated y=x-13 when x=-3

2 answers:

I am Lyosha [343]3 years ago

8 0

For x=-3;
y=-3-13

y=-16

ss7ja [257]3 years ago

3 0

y=x-13

x=-3

y=-3-13=-16

y=-16

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The sum of two numbers is 61.The larger number is 4 more than two times the smaller number. What is the smaller number?

Liula [17]

A + b = 61 a > b a = 2b + 4

2b + 4 + b = 61
3b + 4 = 61
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4 0

2 years ago

Read 2 more answers

Simplify using only POSITIVE exponents:

pickupchik [31]

So here are a few rules with exponents that you should know:

Multiplying exponents of the same base: $x^m*x^n=x^{m+n}$
Dividing exponents of the same base: $x^m\div x^n=x^{m-n}$
Powering a power to a power: $(x^m)^n=x^{m*n}$
Converting a negative exponent to a positive one: $x^{-m}=\frac{1}{x^m}\ \textsf{and}\ \frac{1}{x^{-m}}=x^m$

<h2>1.</h2>

Firstly, solve the outside exponent:

$(2x^3y^7)^{-2}=2^{-2}x^{3*-2}y^{7*-2}=2^{-2}x^{-6}y^{-14}$

Next, convert the negative exponents into positive ones:

$2^{-2}x^{-6}y^{-14}=\frac{1}{2^2x^6y^{14}}=\frac{1}{4x^6y^{14}}$

<u>Your final answer is $\frac{1}{4x^6y^{14}}$ </u>

<h2>2.</h2>

For this, just divide:

$\frac{12x^5y^3}{4x^{-1}}=\frac{12}{4}x^{5-(-1)}y^{3-0}=3x^6y^3$

<u>Your final answer is $3x^6y^3$ </u>

<h2>3.</h2>

For this, convert all negative exponents into positive ones:

$\frac{r^{-7}b^{-8}}{t^{-4}w}=\frac{t^4}{r^7b^8w}$

<u>Your final answer is $\frac{t^4}{r^7b^8w}$ </u>

3 0

3 years ago

29) PLEASE HELP WITH QUESTION.<br><br> MARKING BRAINLIEST + POINTS GIVEN.

Reika [66]

$x^{4} -32 x^{2} -144$ will factor into the following
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$x^{2} =-4$ $x^{2} =36$
x = +/- 2i x = +/- 6

Answer: 2i, 6, -6

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2 years ago

Solve the system of equations. If the system has no solution, say that it is inconsistent. Graph the lines of the system.

Romashka-Z-Leto [24]

Answer:

The solution to the system of the equations will be:

$x=3,\:y=1$

Step-by-step explanation:

Given the system of the equations

$x+y=4$

$x-y=2$

solving the system of the equations

$\begin{bmatrix}x+y=4\\ x-y=2\end{bmatrix}$

$x-y=2$

$-$

$\underline{x+y=4}$

$-2y=-2$

solving

$-2y=-2$

Divide both sides by -2

$\frac{-2y}{-2}=\frac{-2}{-2}$

$y=1$

$\mathrm{For\:}x+y=4\mathrm{\:plug\:in\:}y=1$

$x+1=4$

$x=3$

Therefore, the solution to the system of the equations will be:

$x=3,\:y=1$

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2 years ago

The width of a rectangle is 5 inches less than the length. The perimeter is 24.5 inches. What is the length?

Aloiza [94]

Answer: 7.25 inches

I think, I hoped this helped

5 0

3 years ago