The answer should be on Photomath
Answer:
Refer to Image.
3 went 0 to 5 times
2 went 6 to 10 times
3 went 11 to 15 times
1 went 16 to 20 times
3 went 21 to 25 times
Step-by-step explanation:
When making a histogram, it's good practice to first gather all the frequencies of each number.
1 - 1
3 - 1
4 - 1
6 - 1
10 - 1
11 - 2
12 - 1
16 - 1
20 - 2
22 - 1
Now that we have the total number of frequencies of each number, we can then combine the frequencies for each age range.
0 - 5: 3
6 - 10: 2
11 - 15: 3
16 - 20: 1
21 - 25: 3
The histogram shows that out of the 12 visitors.
3 went 0 to 5 times
2 went 6 to 10 times
3 went 11 to 15 times
1 went 16 to 20 times
3 went 21 to 25 times
<span>6x6 - 4x3 - 2x2 + 3x + 1</span>
All of them because they can't be multiply by nothing more than 1 Exept 27
x²+3x = 9x - 8
Subtract 9x on both sides
x² - 6x = -8
Add 8 on both sides
x² - 6x + 8 = 0
Now you need to find the factors of 8(numbers that multiply to equal 8) that add or subtract to -6.
Factors of 8: 1, 2, 4, 8
2 and 4 add up to 6, if they are both negative they equal -6.
(x - 2)(x - 4) = 0
x - 2 = 0
x = 2
x - 4 = 0
x = 4
x = 2, x = 4