Distance to checkpoint A from starting line = 20 yards.
Then from A to B distance = 12 yards.
Let us take starting point C.
So, it would make a right triangle.
We have AB = 12, AC = 20, we need to find BC, that is Hypotenuse of the right triangle.
According to Pythagoras theorem:
BC = 23.32.
<h3>Therefore, 23.32 yards is the distance from Checkpoint B to the starting line.</h3>
Answer:
15(3y+1)
Step-by-step explanation:
Brainliest PLEASE
Answer: (X-3)^4
Step-by-step explanation:
To shift a function left, add inside the function's argument: f (x + b) gives f (x)shifted b units to the left. Shifting to the right works the same way; f (x – b) is f (x) shifted b units to the right.
Therefore, the equation is 
The general form of a quadratic equation is that which is expressed in a form,
ax² + bx + c = 0
To write the equation in its general form, eliminate the decimal by multiplying the equation by 10. It now becomes,
3x² + 50x - 70 = 0
The value of b is therefore 50 and the answer is the second choice.
if it has a diameter of 8, that means its radius is half that, or 4.
![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=4\\ h=5 \end{cases}\implies V=\cfrac{\pi (4)^2(5)}{3}\implies V=\cfrac{80\pi }{3} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{using~\pi =3.14}{V= 83.7\overline{3}}~\hfill](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ar%3D4%5C%5C%0Ah%3D5%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%284%29%5E2%285%29%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B80%5Cpi%20%7D%7B3%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BV%3D%2083.7%5Coverline%7B3%7D%7D~%5Chfill%20)
