Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
2.74x=58.19
x=21.2372
He only has enough lunch money for 21 full days.
Answer:
The slope is 3 and it's positive
Step-by-step explanation:
(2, 5) and (3, 8)
m=(y2-y1)/(x2-x1)
m=(8-5)/(3-2)
m=3/1
m=3
Answer:
-2
I think it's -2 because you're dividing x by 2 so you'd divide -4 by 2.
