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4 years ago

What is 3.1 rounded to the tenths

Mathematics

2 answers:

Lady bird [3.3K]4 years ago

6 0

It already is rounded to the tenths

.1 is tenth

Arisa [49]4 years ago

6 0

3.1 i hate to say this but if you couldn't find that out, you need to start studying, even i am not this lazy.

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A swimming pool is a rectangular prism. The pool is 36 feet long and 20 feet wide. What is the total amount of water, in cubic f

Sliva [168]

Answer:

$2880\ ft^{3}$

Step-by-step explanation:

The computation of the total amount of water needed could be determined by using the volume formula which is shown below:

$Volume = L \times W \times D$

where

L = length,

W = width,

and D = depth.

Now putting the values to the above formula

$Volume = (36\ ft) \times (20\ ft) \times (4\ ft) \\\\= 2880\ ft^{3}$

Therefore, the total amount of water needed is $2880\ ft^{3}$

We simply applied the above formula

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3 years ago

SCREENSHOT BELOW <br> PLEASE HELP ME

umka2103 [35]

Answer:

9/40?

Step-by-step explanation:

5 0

3 years ago

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Vesnalui [34]

Answer:

Step-by-step explanation:

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3 years ago

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

3 years ago

Answer this question to get marked as brainliest!!!!

Mazyrski [523]

Answer: C

Step-by-step explanation:

A= 1/2(a+b)xh

A=1/2(7+10)x5

A=8.5x5

A=42.5

4 0

3 years ago