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ELEN [110]
4 years ago
8

A box has a length of 5 cm, a width of 10 cm, and a height of 2 cm. The volume of the box is

Mathematics
1 answer:
lora16 [44]4 years ago
5 0
Volume of Cuboid = l * w * h
Substitute their values,
 
V = 5 * 10 * 2
V = 100 cm³

So, your final answer is 100 cm³

Hope this helps!
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How the solve 14% of 27
iogann1982 [59]

Answer:

3.78

Step-by-step explanation:

How you do this problem is by simply multiplying 14% by 27. You have to remember that 14% is equivalent to 0.14, so you have to do 0.14 * 27 and you will get 3.78.

7 0
3 years ago
Read 2 more answers
Need 13&14!! ASAP, will put Brainliest
UNO [17]

Answer:

13- A 14-B

Step-by-step explanation:

You take the formula (x1+x2/2, y1+y2/2) and plug in accordingly. For instance, when you plug the values in for 13, you would get:

x1+-9/2, y1+7/2= -8,2

All you have to do from there is a simple guess and check or plug in each number from the multiple answer choices you have. You should then get A (-7,-3) Do the same with 14, in which you should get B (11,-20)

Sorry for taking so long to answer but hope this kind of helps.

8 0
3 years ago
A circular window is surrounded by a circular frame. The radius of the window is m - 2 and the radius of the full circle formed
Vesnalui [34]

Answer:

Correct answer is:  A = 8 m π

Step-by-step explanation:

In fact, it is necessary to calculate the surface of the circular ring representing the circular window frame:

It's formula:

A = (R² - r²) π    where R = m + 2   and r = m - 2

A = ((m + 2)² - (m - 2)²) π = (m + 2 + m - 2) (m + 2 - m +2) π = 2m · 4 π

A = 8 m π

God with you!!!

5 0
3 years ago
What is the answer plz help like really fast is it 14,42,54,or 170 plz hurry
Ierofanga [76]

Answer:

The answer is 14cm^3

Step-by-step explanation:

8 0
3 years ago
A 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec. What is the rate that the tip of the pers
Dovator [93]

Answer:

9.56 ft/sec

Step-by-step explanation:

We are told that a 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec.

I've attached an image showing  triangle that depicts this;

Thus; dx/dt = 3.4 ft/sec

From the attached image and using principle of similar triangles, we can say that;

9/y = 5.8/(y - x)

9(y - x) = 5.8y

9y - 9x = 5.8y

9y - 5.8y = 9x

3.2y = 9x

y = 9x/3.2

dy/dx = 9/3.2

Now, to find how fast the tip of the shadow is moving away from the lamp post, it is;

dy/dt = dy/dx × dx/dt

dy/dt = (9/3.2) × 3.4

dy/dt = 9.5625 ft/s ≈ 9.56 ft/sec

5 0
3 years ago
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