All categories

3 years ago

Need help due tomorrow plese

Mathematics

1 answer:

Sav [38]3 years ago

4 0

The answers to the questions

You might be interested in

Find the values of the sine, cosine, and tangent for ZA.<br><br> (TOP OF TRIANGLE IS (A))

Sloan [31]

$\bigstar\:{\underline{\sf{In\:right\:angled\:triangle\:ABC\::}}}\\\\$

AC = 7 m
BC = 4 m

⠀⠀⠀

$\bf{\dag}\:{\underline{\frak{By\:using\:Pythagoras\: Theorem,}}}\\\\$

$\star\:{\underline{\boxed{\frak{\purple{(Hypotenus)^2 = (Perpendicular)^2 + (Base)^2}}}}}\\\\\\ :\implies\sf (AB)^2 = (AC)^2 + (BC)^2\\\\\\ :\implies\sf (AB)^2 = (AB)^2 = (7)^2 = (4)^2\\\\\\ :\implies\sf (AB)^2 = 49 + 16\\\\\\ :\implies\sf (AB)^2 = 65\\\\\\ :\implies{\underline{\boxed{\pmb{\frak{AB = \sqrt{65}}}}}}\:\bigstar\\\\$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

☆ Now Let's find value of sin A, cos A and tan A,

⠀⠀⠀

sin A = Perpendicular/Hypotenus = $\sf \dfrac{4}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{4 \sqrt{65}}{65}}$

⠀⠀⠀

cos A = Base/Hypotenus = $\sf \dfrac{7}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{7 \sqrt{65}}{65}}$

⠀⠀⠀

tan A = Perpendicular/Base = ${\sf{\pink{\dfrac{4}{7}}}}$

⠀⠀⠀

$\therefore\:{\underline{\sf{Hence,\: {\pmb{Option\:A)}}\:{\sf{is\:correct}}.}}}$

4 0

2 years ago

What is the value of [(2/3)^0]^-3

sleet_krkn [62]

The answer to this question would be 1/8 or in decimal form it would be 0.125. hopefully this helps with your question.

8 0

3 years ago

Select the correct answer.

dimulka [17.4K]

Answer:

A, y=-6

Step-by-step explanation

Because it isssssssssssssssssssssssssss a watermelon

3 0

3 years ago

To estimate rhe difference below,would you round the numbers to the nearest ten, nearest hundred, or nearest thousand?explain. 8

iogann1982 [59]

To the nearest thousand, because when you are estimating numbers, you always round to the nearest higher place (like the nearest tenth if comparing 26 and 18).

4 0

3 years ago

Simplify the expression.<br> −(−x)3 − x3

Olenka [21]

Answer:

Step-by-step explanation:

-(-x) ^3-x^3

x^3-x^3

4 0

3 years ago