The formula of the kinetic energy is KE = 0.5*m*v^2.
Given m = 80 kg and KE = 4000 J,
4000 = 0.5*80*v^2
v^2 = 100
v = 10 m/s
Answer:
16.405m/s
Explanation:
Given, initial velocity = u = 1.93m/s, acceleration = a = 0.750m/s2, time = t = 19.3s, final velocity = v= ?
Using the first equation of linear motion,
v = u + at
v = 1.93 + 0.750 x 19.3
v = 1.93 + 14.475
v = 16.405m/s
Answer:
Value of magnitude of acceleration will be 
Explanation:
It is given that when a stone is dropped it takes 2.2 sec to reach the ground
(a) As the stone is dropped from the top of building
So its initial velocity
will be 0 m /sec
(b) As the stone is free falling and there is no external force applied on it so its acceleration will be equal to acceleration due to gravity
So value of magnitude of acceleration will be equal to
Answer:
(G) 75.11 ohm
(H) 0.08 A
(I) 46.2 degree
Explanation:
R = 52 ohm
L = 4.8 m H = 4.8 x 106-3 H
C = 330 nF = 330 x 10^-9 F
Vo = 6 V
(G)
f = 5000 Hz
Let the impedance is Z.




(H) Let Io be the peak current

(I) Let Ф be the phase angle


Ф = 46.2 degree
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