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DENIUS [597]
3 years ago
15

Lines l, m, and n are parallel. What is the value of x?Lines l, m, and n are parallel. Parallel lines labeled, top to bottom, l,

m, and n. A transversal forms a fifty-eight degree angle that lies to left of the transversal and below line l and an angle with x degrees that is to right of transversal and above line n.
Mathematics
2 answers:
yulyashka [42]3 years ago
5 0

Answer:

c

Step-by-step explanation:

melisa1 [442]3 years ago
3 0
The answer is 58 because its the same thing.
hope this helps.
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What is -2 1/3- 1 1/3
romanna [79]

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-2\dfrac{1}{3}-1\dfrac{1}{3}=-2\dfrac{1}{3}+\left(-1\dfrac{1}{3}\right)=-\left(2\dfrac{1}{3}+1\dfrac{1}{3}\right)\\\\=-\bigg[(2+1)+\left(\dfrac{1}{3}+\dfrac{1}{3}\right)\bigg]=-\left(3+\dfrac{1+1}{3}\right)\\\\=-3\dfrac{2}{3}

4 0
3 years ago
Read 2 more answers
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
3 years ago
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