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anyanavicka [17]
3 years ago
6

serena is making a large meatloaf that contains ground beef and ground pork. the beef is $3.50 per pound and the pork is $2.00 p

er pound. if she buys more pork then beef and spends $15.25 in total, algebraically model this problem and determine how many pounds of each type of meat was bought.
Mathematics
2 answers:
kvasek [131]3 years ago
8 0

Answer:


Step-by-step explanation:

3.50*2= 7 dollars $2.00 *4.125=8.25     8.25+7=15.25

lakkis [162]3 years ago
4 0

Answer: 2.5 pounds of beef  and 3.25 pounds of pork

Step-by-step explanation:

Hi, the answer is incomplete because is lacking how much more pork she bought. <em>She bought 0.75 pounds more pork than beef and spends $15.25</em>, is the complete form.

So, to answer this question we have to analyze the information given:

  • <em>Beef: $3.50 per pound </em>
  • <em>Pork: $2.00 per pound </em>
  • <em>Pounds of beef = x </em>
  • <em>Pounds of pork = x + 0.75 </em>
  • <em>Total cost : $15.25</em>

So, the equation is:

3.50x + 2 (x+0.75) = 15.25

3.50x +2x + 1.5 =15.25

5.50 x = 15.25 -1.5

5.50x = 13.75

x = 13.75/5.50  

x = 2.5 pounds of beef

Replacing the value of x in the Pork's equation:

Pounds of pork = x +0.75 = 0.75 +2.5 = 3.25 pounds of pork

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From the image attached:

AB divided into 4 similar parts, hence

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Note that the rule of the mid-point states that:

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Then lets solve for points E, F, D

Since A (-3 , -1) and B (6 , -3),

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Then F = [(3/2 + 6)/2 , (-2 + -3)/2]

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Since D is the mid-point of AE, A (-3 , -1), E (3/2 , -2)

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Then  y-coordinate of G is =  -3

Since DG ⊥ BC

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So  G has similar x-coordinate of D

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6 0
1 year ago
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Step-by-step explanation:

7 0
3 years ago
Jacob leaves his summer cottage and drives home. After
krok68 [10]

Answer:

A linear relationship can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If this line passes through the points (a, b) and (c, d) then the slope can be written as:

a = (a - c)/(b - d)

Here y will represent the distance between Jacob and his house, and the variable x represents the time that he has ben driving.

In this case, we know that after driving for 5 hours, he is 112km from home.

Then we can write this point as (5h, 112km)

We also know that after 7 hours he is 15km from home.

Then we can write this point as (7h, 15km)

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Then the equation is:

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This means that we need to replace x by 12h, and y by 15km, then we get:

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then the equation will be:

y = (-48.5 km/h)*x + 354.5 km

Now we want to answer: How long had Jacob been driving when he was 209 km from  home?

Then we need to only replace y by 209km, and solve for x:

209km = (-48.5 km/h)*x + 354.5 km

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So he is 209km away from his home after driving for 3 hours.

6 0
3 years ago
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