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Reil [10]
3 years ago
6

Why forces are balanced and unbalanced? need help with this the lesson is tommorow

Physics
2 answers:
Naya [18.7K]3 years ago
4 0
"Balanced" means that if there's something pulling one way, then there's also
something else pulling the other way. 

-- If there's a kid sitting on one end of a see-saw, and another one with the
same weight sitting on the other end, then the see-saw is balanced, and
neither end goes up or down.  It's just as if there's nobody sitting on it.

-- If there's a tug-of-war going on, and there are 300 freshmen pulling on one
end of a rope, and another 300 freshmen pulling in the opposite direction on
the other end of the rope, then the hanky hanging from the middle of the rope
doesn't move.  The pulls on the rope are balanced, and it's just as if nobody
is pulling on it at all.

-- If a lady in the supermarket is pushing her shopping cart up the aisle, and her
two little kids are in front of the cart pushing it in the other direction, backwards,
toward her.  If the kids are strong enough, then the forces on the cart can be
balanced. Then the cart doesn't move at all, and it's just as if nobody is pushing
on it at all.

From these examples, you can see a few things:

-- There's no such thing as "a balanced force" or "an unbalanced force".
It's a <em><u>group</u> of forces</em> that is either balanced or unbalanced.

-- The group of forces is balanced if their strengths and directions are
just right so that each force is canceled out by one or more of the others.

-- When the group of forces on an object is balanced, then the effect on the
object is just as if there were no force on it at all.
pav-90 [236]3 years ago
4 0
Because the way it's being set down on . It's like newtons law, what stays at rest stays unless an outside force does something. 
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4 years ago
The earth exerts a gravitational force of 850N on John. What is Johns mass in kg
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Answer:

86.73 kg

Explanation:

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Let's plugin our numbers

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2 years ago
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Paraphin [41]

assuming the reference line to measure the height for gravitational potential energy lying at the equilibrium position

m = mass attached to the spring = 10.00 kg

k = spring constant of the spring = 250 N/m

h = height of the mass above the reference line or equilibrium position = 0.50 m

x = compression of the spring = 0.50 m

v = speed of mass = 2.4 m/s

A = maximum amplitude of the oscillation

v' = speed of mass at the maximum amplitude location = 0 m/s

using conservation of energy between the point where the speed is 2.4 m/s  and the highest point at which displacement is maximum from equilibrium

kinetic energy + spring potential energy + gravitational potential energy = kinetic energy at maximum amplitude + spring potential energy at maximum amplitude  + gravitational potential energy at maximum amplitude

(0.5) m v² + m g h + (0.5) k x² = (0.5) m v'² + m g A + (0.5) k A²

inserting the values

(0.5) (10) (2.4)² + (10) (9.8) (0.50) + (0.5) (250) (0.50)² = (0.5) (10) (0)² + (10) (9.8) A + (0.5) (250) A²

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