Which three steps, placed in the proper order, are required for a nuclear chain reaction?.
1 answer:
There are three basic steps in a nuclear fission chain reaction are Initiation, Propagation, Termination.
<h3>What are the three steps of nuclear fission ?</h3>1. Initiation
The nuclear fission of is started by the absorption of a neutron; a single atom must react in order for the chain reaction to begin.
2. Propagation:-
With each stage producing additional product, this component of the process is repeated repeatedly. When splits apart, neutrons are released, which start the nuclear fission of more uranium atoms.
3. Termination:
The chain will come to an end eventually. Termination might take place if the reactant is exhausted or if the subsequent neutrons in the chain leave the sample without being absorbed by
.
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Answer:
q = 3.6 10⁵ C
Explanation:
To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth
r = 6 , 37 106 m
E = k q / r²
q = E r² / k
q =
q = 4.5 10⁵ C
Now let's calculate the charge on the planet with E = 222 N / c and radius
r = 0.6 r_ Earth
r = 0.6 6.37 10⁶ = 3.822 10⁶ m
E = k q / r²
q = E r² / k
q =
q = 3.6 10⁵ C
Speed of any freely falling object is always same. Provided, both are left to fall from the same height. If you perform this experiment in a perfect vacuum or near vacuum laboratory, both of them will reach ground with same velocity this is because there is no resistance to their motion. This is always true no matter where you go and perform this experiment.
It can be easily proved from conservation of mechanical energy. Why conserving energy? because there are no forces acting on the freely falling objects other than conservative force(mg).
It can be easily proved from conservation of mechanical energy. Why conserving energy? because there are no forces acting on the freely falling objects other than conservative force(mg).