Question

At an instant in time, the electric and magnetic fields of an electromagnetic wave are given by - -6.25 x 10-3 v/m and B = -2.08 x 10-111 . Find the Poynting vector for this wave. (Express your answer in vector form.) W/m2 S =

Answer 1

Answer:

Poynting vector, $S=1.03\times 10^{7}\ W/m^2$

Explanation:

It is given that, The electric and magnetic fields of an electromagnetic wave are given by :

Electric field, $E=6.25\times 10^{-3}\ V/m$

Magnetic field, $B=2.08\times 10^{-11}\ T$

We need to find the Poynting vector for this wave. the Poynting vector is given by :

$S=\dfrac{1}{\mu_o}EB$

$S=\dfrac{1}{4\pi \times 10^{-7}}\times 6.25\times 10^{-3}\times 2.08\times 10^{-11}$

$S=1.03\times 10^{7}\ W/m^2$

So, the Poynting vector for this wave is $1.03\times 10^{7}\ W/m^2$. Hence, this is the required solution.