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Novay_Z [31]
3 years ago
11

The natural enzyme reaction in food slowly breaks it down and eventually causes it to spoil. what 2 things halt this enzyme reac

tion and help preserve the food?
microwaving
cooking at high temperature
storing properly in the refrigerator
blanching and canning
Physics
2 answers:
ollegr [7]3 years ago
4 0

Answer: the answer is storing properly in refrigeration.

Explanation:

katrin2010 [14]3 years ago
3 0

Answer:  storing food in the fridge

Explanation:

You might be interested in
What happens to light waves at the interface between different media?
nevsk [136]

Answer:

Refractive motion is the impact of a light wave that travels from medium to medium in an angle away from normal, where the direction of light varies. Light is refracted when it crosses the air-to-glass interface and moves slower.

Explanation:

Refractive motion is the impact of a light wave that travels from medium to medium in an angle away from normal, where the direction of light varies. Light is refracted when it crosses the air-to-glass interface and moves slower.

Hope this helps.

6 0
3 years ago
In a summer storm, the wind is blowing at a velocity of 8 m/s north. Suddenly in 3 seconds, the winds velocity is 23 m/s north.
cricket20 [7]

Answer:a=v-u/t

=23-8/3

=5m/s hope you got your answer

Explanation:

8 0
3 years ago
How many days of a diet of 1910 large calories are equivalent to the gravitational energy change from sea level to the top of Mo
andreyandreev [35.5K]

Answer:

0.58 days is needed

Explanation:

Gravitational energy change from a height change equal to 8848 m for a mass of 53 kg is:

m*g*h = 53*9.81*8848 = 4600340.64 J = 4600.34 kJ

4.184 kJ are equivalent to 1 kcal, then:

4.184 kJ / 4600.34 kJ = 1 kcal / x kcal

x = 4600.34/4.184

x = 1099.5 kcal or large calories

The diet is 1910 kcal/day, then you need 1099.5/1910 = 0.58 days

3 0
3 years ago
A 0.05 kg ball is attached to the end of a 0.5 m long string. The ball is spun around a circle with a period of 0.20 s. What is
Gekata [30.6K]

The ball spins once around the circle in 0.20 s, meaning it travels a distance equal to its circumference in that time, giving it a linear speed of

<em>v</em> = (2<em>π</em> (0.5 m)) / (0.20 s) = 5<em>π</em> m/s ≈ 15.708 m/s

Use this compute the magnitude of the centripetal acceleration <em>a</em> :

<em>a</em> = <em>v</em>²/ (0.5 m) = 50<em>π</em>² m/s² ≈ 493.48 m/s²

Use Newton's second law to compute the mangitude of the tension <em>F</em> in the string:

<em>F</em> = (0.05 kg) <em>a</em> = 5/2 <em>π</em>² N ≈ 24.674 N ≈ 25 N

4 0
3 years ago
Sound travels in a medium of density 4.2e3 kg/m3 with a speed of 4.le3 m/s. Calculate the bulk modulus of the medium. (1 point)
WARRIOR [948]

Answer : The correct option is, (A) 7.06\times 10^{10}Pa

Explanation :

The formula used for speed of sound wave is:

v=\sqrt{\frac{B}{\rho}}

where,

v = speed of sound wave = 4.1\times 10^3m/s

\rho = density of medium = 4.2\times 10^3kg/m^3

B = bulk modulus = ?

As the formula is,

v=\sqrt{\frac{B}{\rho}}

Squaring on both the sides, we get:

B=v^2\times \rho

Now put all the given values in the above formula, we get:

B=(4.1\times 10^3m/s)^2\times (4.2\times 10^3kg/m^3)

B=7.06\times 10^{10}Pa

Therefore, the bulk modulus of the medium is 7.06\times 10^{10}Pa

5 0
3 years ago
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