The local area was once an aquatic environment
Molar mass of C is 12.01g/mol.
Molar mass of H is 1.01g/mol.
Molar mass of O is 16.00g/mol.
If we have 19 atoms of C, 38 atoms of H, and 1 atom of O, then we have:
19*12.01+38*1.01+1*16.00=282.57g/mol
282.57g/mol is the molar mass of the pheromone molecule.
Supposing that "<span>1.8 10-12 g" is 1.8*10^(-12)g then, this quantity of pheromones, shoud be divided by the molar mass of the pheromone molecule:
1.8*10^(-12)/282.57g/mol=6.37*10^(-15)moles
Using now Avogadro's number of molecules in 1mol (6.02*10^(23)) it is possible to know how many molecules are there in this pheromone quantity.
</span>6.02*10^(23)/6.37*10^(-15)=9.45*10^(37)molecules
So, in this quantity of the pheromone there are approximately 9.45*10^(37)molecules of it.
In pollination, the brightly coloured petals and external agents like wind,water,air and insects are involved. But, in fertilization the male reproductive organs and the female reproductive organs are involved (I.e. stamen and the stigma).
Answer: a law
Explanation: If you need the definition too. A descriptive statement or equation that reliably predicts events under certain conditions.
