All categories

3 years ago

Really easy math problem 5pts!!!

Mathematics

2 answers:

Alexeev081 [22]3 years ago

6 0

Answer:

I think I is the second one

kogti [31]3 years ago

4 0

You're given two angles and the side not between them are congruent, so the AAS theorem applies. (2nd selection)

You might be interested in

If x = 2/9 and y = 3/7 work out the value of x + y

faltersainse [42]

Answer:

$\boxed{\sf \dfrac{41}{63}}$

Step-by-step explanation:

hi, it means that we have to compute

$\dfrac{2}{9}+\dfrac{3}{7}=\dfrac{7*2+3*9}{7*9}=\dfrac{14+27}{7*9}=\dfrac{41}{63}$

8 0

3 years ago

Read 2 more answers

Willy and Bill kept track of the distance each rode on his bike last week. Willy rode a total of 121.3 kilometers. Bill rode a t

iogann1982 [59]

C.
Willy and Bill rode an equal distance on their bikes

Hope it help! :D

8 0

3 years ago

Read 2 more answers

The quadrilateral shown is rotated 90° clockwise about the origin. In which quadrant is the image of the quadrilateral located?

Viktor [21]

Answer:

Option (2). 1

Step-by-step explanation:

Coordinates of point A, B, C and D are,

A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).

Quadrilateral ABCD when rotated 90° clockwise about the origin,

Rule for the rotation of the vertices,

(x, y) → (y, -x)

Following the rule of rotation coordinates of the image points,

A(-4, 4) → A'(4, 4)

B(-2, 4) → B'(4, 2)

C(-2, 1) → C'(1, 2)

D(-4, 3) → D'(3, 4)

Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.

Option (2) is the correct option.

4 0

3 years ago

Open the photo to see question please...

9966 [12]

Answer:c

cccg bgfv

Step-by-step explanation:

8 0

3 years ago

A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l

Daniel [21]

Answer:

C. 1000 loss.

Step-by-step explanation:

Let x represent purchase price of each car.

We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.

We can represent the car that dealer sold with 25% profit to find purchase price as:

$x+0.25x=20,000$

$1.25x=20,000$

$\frac{1.25x}{1.25}=\frac{20,000}{1.25}$

$x=16,000$

Therefore, the purchase price of 1st car was $16,000.

We can represent the car that dealer sold with 20% loss to find purchase price as:

$x-0.20x=20,000$

$0.80x=20,000$

$\frac{0.80x}{0.80}=\frac{20,000}{0.80}$

$x=25,000$

Therefore, the purchase price of 2nd car was $25,000.

The total purchase price of both cars would be $16,000+25,000=41,000$

The total sale price of both cars $20,000+20,000=40,000$ .

We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.

Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.

4 0

3 years ago