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rewona [7]
3 years ago
7

Solve for x 2cos(x + 40 ^ 0) = 1/2 for r 0<= x<=360^ Worth 6 marks

Mathematics
1 answer:
Mama L [17]3 years ago
6 0
SOLVE THE EQUATIONS
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Use the gcf and the distributive property to express the sum as a product 20 35
Maslowich
Common factor of 20= 1,2,4,5,10.......
common factor of 35=1,5,7.............
so here we find that 1 and 5 r the common factors 
but the GCF of 20 and 35 is 5
so,
by using GCF the distributive property is : 5(4+7)
5 0
3 years ago
Evaluate √x^2 − y^2 when x^2 =33 and y^2 =15
Andre45 [30]

Answer:

3√2

Step-by-step explanation:

In this question, we are asked to get the value of √ ( x²-y² ), while the value of x² and y² are given to be 33 and 15 respectively.

Hence, x² =33 and y² = 15.  

Putting the values of x² and y² in the above expression we get,

√ ( x²-y² ) = √ ( 33-15) = √18 =3√2. (Answer)

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3 years ago
15. If gasoline costs $4.02 per gallon, your tank holds 13 gallons, and your car averages 26 miles per gallon,
Shtirlitz [24]

Answer: a) 338 miles

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Step-by-step explanation: To get the amount of miles that your car can drive before running out of gas, you just multiply how many gallons you have by how many miles each gallon lasts. Then, to get the cost of all the gas, you multiply the cost of the gas by how many gallons you need.

5 0
3 years ago
9000 dollars is placed in an account with an annual interest rate of 8%. How much will be in the account after 17 years, to the
Fed [463]

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$33,300.16

Step-by-step explanation:


7 0
3 years ago
An electronics store makes a profit of $72 for every television sold and $90 for every computer sold. The manager’s target is to
enyata [817]

Answer:

option A

Step-by-step explanation:

Let x be the number of television sold

and y be the number of computer sold

An electronics store makes a profit of $72 for every television sold and $90 for every computer sold.

Profit for x television is 72x

Profit of y computer is  90y

Total profit is 72x+90y

sales profit is atleast 360

so inequality becomes 72x+90y >360

graph is attached below

(5,2) lies on the shaded part, so (5,2) is our solution

(3,3) lies on the shaded part, so (3,3) is our solution

(1,4) lies on the shaded part, so (1,4) is our solution

(4,0) (2,2) (1,1) and (1,0) does not lies on the shaded part

So option A is correct


5 0
3 years ago
Read 2 more answers
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