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rewona [7]
2 years ago
7

Solve for x 2cos(x + 40 ^ 0) = 1/2 for r 0<= x<=360^ Worth 6 marks

Mathematics
1 answer:
Mama L [17]2 years ago
6 0
SOLVE THE EQUATIONS
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Helllllllllllilllllyyeneyneyn
Deffense [45]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
A gym owner has some purple weights and some white weights. The purple weights are 10 kilograms each, and the white weights are
snow_lady [41]

Answer: 3,9

Step-by-step explanation:

Given

A gym owner has purple and white weights that measure 10 kg and 6 kg each

respectively.

They weigh 84 kg in total

suppose there x purple and y white weights

\therefore x+y=12\quad \ldots(i)\\\Rightarrow 10x+6y=84\quad \ldots(ii)\\\\\text{Solving }(i)\ \text{and }(ii)\\\\

x=3,\ y=9

Thus, there are 3 purple and 9 white weights.

8 0
2 years ago
Luisa is making a histogram for the following set of data: 11, 77, 35, 5, 76, 34, 89, 92, 22. Which is an appropriate first inte
creativ13 [48]

Answer:

Step-by-step explanation:

The given data is 11, 77, 35, 5, 76, 34, 89, 92, 22

The total number of items in the data is 9. The width of each class interval would be gotten by dividing the difference between the minimum and maximum items in the data by the number of class intervals. From the information given,

Minimum item = 5

Maximum item = 92

Difference = 92 - 5 = 7

Class width = 87/10 = 8.7

By approximation, it is closest to 10

Therefore, the appropriate class group is 0 to 10

7 0
2 years ago
Read 2 more answers
Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are inches long, inches wide, and 8 inche
allochka39001 [22]

Answer:

- The number of small boxes that will fill the large box 1 = 64

- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

For large box 1,

Length = L = 24.25 inches

Width = W = 18 inches

Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

Length = L = 20.5 inches

Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

7 0
2 years ago
Please help me asap​
puteri [66]

1. 3.875

2. .35

3. 9 3/4

3 0
3 years ago
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