3a+b+c
The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.
So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:
16a+8b-6c - 2*(5a+3b-4c) =
16a+8b-6c -10a-6b+8c =
6a+2b+2c
half of that is
(6a+2b+2c)/2 = 3a+b+c
Answer:
"Team C scored 130 points."
Step-by-step explanation:
Let x represent how many points team B scored.
Team A: 3x + 6
Team B: x
Team C: x + 45
Total: 476 points
476 = (x) + (3x + 6) + (x + 45)
476 = x + 3x + 6 + x + 45
476 = 5x + 51
425 = 5x
x = 85
Team A:
3(85) + 6
= 261 pts
Team B:
= 85 pts
Team C:
(85) + 45
= 130 points
Answer: It is equal to the measure of angle C.
Step-by-step explanation:
If we know that Triangle ABC isosceles, then that means two sides and two angles are congruent to each other. Angle A must the topmost angle, and Angle B and C are probably the base angles. So, saying that, the base angles and sides are congruent to each other. Hence, Angle B must be equal to Angle C.
<em>Answer:</em>
<em>$5 for 8 pens</em>
<em></em>
<em>Step-by-step explanation:</em>
<em>0.625 times 8= 5 dollars</em>
<em>0.625 times 50= 31.25</em>
<em>which is way cheaper</em>
Answer: y = 7- 5x
Step-by Step Explanation: The variable x is multiplied by a larger value here; it's multiplied by 5. So I should expect that my y-values will grow fairly quickly. This means that I should expect a fairly "tall" graph.
First I'll do the T-chart.
T-chart
This equation is an example of a situation in which you will probably want to be particular about the x-values you pick. Because the x is multiplied by a relatively large value, the y-values grow quickly. For instance, you probably wouldn't want to use x = 10 or x = –7 as inputs. You could pick larger x-values if you wished, but your graph would very quickly get awfully tall.
I can see, from my T-chart, that my y-values are getting pretty big on either end (that is, in the positive numbers above the horizontal axis, and in the negative numbers below). I don't want to waste time computing points that will only serve to make my graph ridiculously large, so I'll quit with what I've got so far. But I'm glad I plotted more than just two points, because lines that start edging close to vertical can easily go wrong, if I'm not neat in my work.
Here's my graph:
y = 7 - 5x