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Natasha_Volkova [10]
4 years ago
12

What is the first step you would take solving for k in 4k + 12 = -28

Mathematics
1 answer:
valkas [14]4 years ago
5 0

Answer:

The first step I would take is subtract 12 from both sides.

Step-by-step explanation:

i hope this helps!

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What is the answer to MP?
Fittoniya [83]

Answer:

MP = 17

Step-by-step explanation:

Since N is the midpoint of MO then MN = NO = 7

NO + OP = NP , then

7 + OP = 10 ( subtract 7 from both sides )

OP = 3

Then

MP = MN + NO + OP = 7 + 7 + 3 = 17

6 0
3 years ago
An angle measures 30° less than the measure of its supplementary angle. What is the measure of each angle?
xxMikexx [17]

Answer:

The measures of each would be:

105° and 75°

Step-by-step explanation:

Supplementary angles are two angles whose measures sum up to 180° or they form a straight line.

So if an angle measures 30° less than the measure of its supplementary, it wold mean that both angles together is equal to 180°.

∠1 = x

∠2 = x-30°

∠1 + ∠2 = 180°

So here we plug in our equations:

∠1 + ∠2 = 180°

x + x - 30° = 180°

2x - 30° = 180°

We solve for the x then:

Add 30° on both sides of the equation:

2x - 30° + 30° = 180° + 30°

2x = 210°

Divide both sides by 2:

2x/2 = 210°/2

x = 105°

∠1 = 105°

Now we solve for the second angle:

∠1 + ∠2 = 180°

105° + ∠2 = 180°

Subtract 105° from both sides of the equation:

105° + ∠2 - 105° = 180° - 105°

∠2 = 75°

7 0
4 years ago
Use the upper and lower sums to approximate the area of the region using the given number of subintervals (of equal width)
Mashutka [201]
From the figure shown, the interval is divided into 5 equal parts making each subinterval to be 0.2.

Part A:

y= \sqrt{1-x^2}

The approximate the area of the region shown in the figure using the lower sums is given by:

 Area= [y(0.2)\times0.2]+[y(0.4)\times0.2]+[y(0.6)\times0.2]+[y(0.8)\times0.2] \\ +[y(1)\times0.2] \\  \\ =[\sqrt{1-(0.2)^2}\times0.2]+[\sqrt{1-(0.4)^2}\times0.2]+[\sqrt{1-(0.6)^2}\times0.2] \\ +[\sqrt{1-(0.8)^2}\times0.2]+[\sqrt{1-(1)^2}\times0.2] \\  \\ =(0.9798\times0.2)+(0.9165\times0.2)+(0.8\times0.2)+(0.6\times0.2)+(0\times0.2) \\  \\ =0.196+0.183+0.16+0.12=0.659



Part B:

The approximate the area of the region shown in the figure using the lower sums is given by:

 Area= [y(0)\times0.2]+[y(0.2)\times0.2]+[y(0.4)\times0.2]+[y(0.6)\times0.2] \\ +[y(0.8)\times0.2] \\ \\ =[\sqrt{1-(0)^2}\times0.2]+[\sqrt{1-(0.2)^2}\times0.2]+[\sqrt{1-(0.4)^2}\times0.2] \\ +[\sqrt{1-(0.6)^2}\times0.2] +[\sqrt{1-(0.8)^2}\times0.2] \\ \\ =(1\times0.2)+(0.9798\times0.2)+(0.9165\times0.2)+(0.8\times0.2)+(0.6\times0.2) \\ \\ =0.2+0.196+0.183+0.16+0.12=0.859



Part C:

The approximate area of the given region is given by

Area= \frac{0.659+0.859}{2} = \frac{1.518}{2} =0.759
7 0
4 years ago
Film travels through a projector at the rate of 170 feet per minute. How many feet of flim are in a motion picture that last 120
Vaselesa [24]

120x170=20400

hope it helps

6 0
3 years ago
What is the value of x in this problem?
Alex787 [66]

it will be 63.1(56TAN) or 93.549

6 0
4 years ago
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