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Zigmanuir [339]
3 years ago
15

Solve for the variable: 3(2x+1)-5x=x+3

Mathematics
2 answers:
Taya2010 [7]3 years ago
5 0
3(2x+1)-5x=x+3
6x+3-5x=x+3  then combine like terms
x+3=x+3
  -3    -3
x=x so x would be all real numbers
KonstantinChe [14]3 years ago
4 0
Simplify the left side.

Simplify each term.

Apply the distributive property.

3(2x)+3⋅1−5x=x+33(2x)+3⋅1-5x=x+3

Multiply 22 by 33 to get 66.6x+3⋅1−5x=x+36x+3⋅1-5x=x+3

Multiply 33 by 11 to get 33.6x+3−5x=x+36x+3-5x=x+3

Subtract 5x5x from 6x6x to get xx.x+3=x+3x+3=x+3

Move all terms containing xx to the left side of the equation.

Since xx contains the variable to solve for, move it to the left side of the equation by subtracting xx from both sides.

x+3−x=3x+3-x=3

Simplify the left side of the equation.

Subtract xx from xx to get 00.0+3=30+3=3

Add 00 and 33 to get 33.3=33=3

Since 3=33=3, the equation will always be true for any value of xx.

All real numbers
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Observe the graph below. This graph represents the scenario.

The question is ill formated, the complete question is

In a simulation, a moving object accelerates from rest to 4 meters per second in 2 seconds. For the following three seconds, it increases linearly until it reaches a speed of 10 meters per second. Following three seconds at that speed (acceleration = 0), the item progressively decelerates until it comes to rest two seconds later. Draw the graph of this scenario for 10 seconds?

I'll describe how the graph may show.

It will move diagonally upward from time 0 to 2 seconds until it reaches the y axis at a speed of 4 m/s.

Then, from 2 to 5, the position will move up diagonally until it reaches the y axis at a speed of 10 m/s.

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Observe the graph below. This graph represents the scenario.

Learn more about Acceleration here-

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