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lesantik [10]
3 years ago
15

Three workers sort 66 boxes in a day. One of the workers is three times more productive than the second worker and twice as prod

uctive as the third worker. How many boxes did the second most productive worker sort?
Mathematics
1 answer:
Lelechka [254]3 years ago
7 0
1 worker =x

2 worker = \frac{worker1}{2}= \frac{x}{3}

3 worker = \frac{worker1}{3}= \frac{x}{3}

so:

66=x+ \frac{x}{3}+ \frac{x}{2}

66=x+\frac{2x}{6}+ \frac{3x}{6}

66*6=6x+2x+3x

396=11x

x=36

so:

worker 1 sorted 36 boxes
worker 2 sorted 18 boxes
worker 3 sorted 12 boxes
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Iteru [2.4K]

Step-by-step explanation:

Given : m∥n , ∠1= 50° , ∠2= 48° , and line s bisects ∠ABC

To prove = ∠3= 49°

Solution:

In figure, m∥n cut by traversal t.

So,  ∠DEF = ∠ABC(alternative exterior angles)

∠1 + ∠2 = ∠4 + ∠5

∠ABC = ∠1 + ∠2 = 50° + 48° = 98°

Also given that s bisect angles ∠ABC.

∠4 = ∠5

∠ABC = ∠4 + ∠5 = 98°

∠4 + ∠4 = 98°

2∠4 = 98°

∠4 = 49°

∠4= ∠3 = 49° (vertically opposite angles)

∠3 = 49° ,hence proved

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Oksanka [162]

Answer:

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Divide the price change by the old price to find the price increase in percentage:

9.60 \div 20 = 0.48 \\ 0.48 \times 100\% = 48\%

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3 years ago
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\text{For a given area and circumference}:\\\\A=153.86,\ C=43.96,\ r=7\\\\\dfrac{A}{C}=\dfrac{153.86}{43.96}=3.5=\dfrac{7}{2}=\dfrac{r}{2}\\\\\dfrac{A}{C}=\dfrac{r}{2}

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