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Vladimir [108]
3 years ago
14

 K is the midpoint of . if = 3x + 1 and     , find the length of

Mathematics
1 answer:
jarptica [38.1K]3 years ago
4 0
3x + 1 = 1/3x + 9 Multiply through by 3 
<span>9x + 3 = x + 27 Subtract x </span>
<span>8x + 3 = 27 Subtract 3 </span>
<span>8x = 24 </span>
<span>x = 3 </span>

<span>AK = 3*3 + 1 = 10 </span>

<span>AB = 2*AK = 20</span>
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1) Find the lump that must be deposited today to have a future value of $ 25,000 in 5 years if funds earn 6 % componded annually
Hoochie [10]

Answer: $ 18681.45

Step-by-step explanation:

Given: Future value : FV=\$25,000

The rate of interest : r=0.06

The number of time period : t=5

The formula to calculate the future value is given by :-

\text{Future value}=P(1+i)^n, where P is the initial amount deposited.

\Rightarrow\ 25000=P(1+0.06)^5\\\\\Rightarrow\ P=\dfrac{25000}{(1.06)^5}\\\\\Rightarrow\ P=18681.4543217\approx=18681.45

Hence, the lump that must be deposit today : $ 18681.45

4 0
3 years ago
-1/3x=2/5x2/3 solve this
Nat2105 [25]
I hope this helps you

8 0
3 years ago
If y(x)=4x what is x when y(x)=4?​
Fofino [41]

Answer:

1

Step-by-step explanation:

y(x)=4x

y(x)=4

<=>4x=4

<=>x=1

4 0
3 years ago
If sin ? = 12 over 37, use the pythagorean identity to find cos ?. cos ? = ± 35 over 37 cos ? = ± 23 over 37 cos ? = ± 35 over 1
kotegsom [21]
If sin x = 12/37, we have to find cos x.
The identity:
sin² x + cos² x = 1
( 12/37)² + cos² x = 1
144 / 1369 + cos² x = 1
cos² x = 1 - 144/1369
cos² x = 1369/1369  - 144/1369
cos² x = 1225 / 1369
cos x = +/- √ 1225/1369 = +/- 35/37
Answer:
A ) cos ? = +/- 35 over 37
7 0
3 years ago
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Please help with these two questions?
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4 0
4 years ago
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