If α and β are the Roots of a Quadratic Equation ax² + bx + c then :
✿ Sum of the Roots : α + β 
✿ Product of the Roots : αβ 
Let the Quadratic Equation we need to find be : ax² + bx + c = 0
Given : The Roots of a Quadratic Equation are 6 and 3
⇒ α = 6 and β = 3
Given : The Leading Coefficient of the Quadratic Equation is 4
Leading Coefficient is the Coefficient written beside the Variable with Highest Degree. In a Quadratic Equation, Highest Degree is 2
Leading Coefficient of our Quadratic Equation is (a)
⇒ a = 4
⇒ Sum of the Roots 
⇒ -b = 9(4)
⇒ b = -36
⇒ Product of the Roots 
⇒ c = 18 × 4
⇒ c = 72
⇒ The Quadratic Equation is 4x² - 36x + 72 = 0
Option D is the correct answer
A triangle’s angles must add up to 180 to be a proper triangle. Option A, B, and C added up all equal 180, whereas option D only equals 150.
Answer:
sin O = 
Step-by-step explanation:
given tan O =
= 
Then this is a right triangle with legs 3 and 4
Using Pythagoras' identity then the hypotenuse (h ) is
h =
=
= 5, hence
sin O =
= 